不允许使用抽象类类型为“ QuarterBack”的对象

Question

我有一个名为Player的抽象基类，它有一个名为QuarterBack的子类。如果我尝试实例化QuarterBack的对象，则会收到2条错误，指出：a）不允许抽象类类型为“ QuarterBack”的对象：b）'QuarterBack'：无法实例化抽象类

Player中有两个纯虚拟函数，分别称为getPlayerPosition（）和play（）。但是，我只对getPlayerPosition（）报错，应该将Quarter back作为Player的具体子类，但是编译器说QuarterQuar仍然是一个抽象类。

我不知道从哪里开始解决这些错误。

class Player {
private: 
string fname, lname, position;
int playerID;
static int numPlayers;
public:
Player(string fname, string lname, string position, int playerID) {
    this->fname = fname;
    this->lname = lname;
    this->position = position;
    this->playerID = playerID;
    ++numPlayers;
    cout << "Creating Player" << endl;
}
~Player() {
    cout << "Destroying Player" << endl;
}

string getName() {
    return fname + " " + lname;
}

virtual string getPlayerPosistion() = 0; // pure virtual function

virtual int play() = 0; // pure virtual function

string toString() {
    string temp = "Name: " + fname + " " + lname + " | Position: " + position + " | Number: " + to_string(playerID);
    return temp;
}
};


class QuarterBack : public Player {
private:
string fname, lname, position;
int playerID;
public:
QuarterBack(string fname, string lname, string position, int playerID) : Player(fname, lname, position, playerID) {
    this->fname = fname;
    this->lname = lname;
    this->position = position;
    this->playerID = playerID;
    cout << "Creating QuarterBack " << endl;

}
~QuarterBack() {
    cout << "Destroying QuarterBack" << endl;
}

string getName() {
    return fname + " " + lname;
}

string getPlayerPosition() {
    return position;
}

int play() {
    return 0;
}
};

int main()
{
string firstN, lastN, position;
int ID;
firstN = "Tom";
lastN = "Johnson";
position = "QuarterBack";
ID = 17;
QuarterBack qb(firstN, lastN, position, ID);
cout << qb.toString() << endl;

system("pause");
return 0;
}