Question

我正在建立一个分页系统，可以对我网站上的文章进行分页。

目标：对文件数组进行分页（每页7个元素）

我遇到一个问题，我已经进行了5个多小时的故障排除...这是逻辑问题，如果我做错了，请纠正我。

好的。因此，我在一个文件夹中放了26个虚拟物品（字母）。让我们找到其中的文件数量...我将结果称为：变量X。

要获取分页页数，请执行以下操作： X除以7。显然，这可以输出浮点数而不是整数。。因此，请使用“ cint”将结果四舍五入-始终将其向上舍入。让我们将页数称为“ Z”。

所以我和我的新朋友Z想要告诉某种函数来获取这些文章。我用以下等式找到了我想展示的文章的开头和结尾。

$ start = Z * 7-7

$ end = Z * 7

这些方程生成

第1页的0至7。预期结果（不现实）：

a，b，c，d，e，f，g。

第2页为8到15。预期结果（不是现实）。

h，i，j，k，l，m，n。

依此类推...

因此，使用我的上级大脑（sike），我设法为第1页生成了以下输出：

CHOOSE PAGE: 1 2 3 4 
Youre at page 1
Theres 26 articles

Showing 0 to 7

a - Thursday, 4th of April 2019 @ 20:54:02
b - Thursday, 4th of April 2019 @ 20:54:04
c - Thursday, 4th of April 2019 @ 20:54:08
d - Thursday, 4th of April 2019 @ 20:54:10
e - Thursday, 4th of April 2019 @ 20:54:13
f - Thursday, 4th of April 2019 @ 20:54:15
g - Thursday, 4th of April 2019 @ 20:54:18

但是，非常奇怪的是，当我转到第2页时，我会...陷入困境。

CHOOSE PAGE: 1 2 3 4 
Youre at page 2
Theres 26 articles

Showing 7 to 14

h - Thursday, 4th of April 2019 @ 20:54:22
i - Thursday, 4th of April 2019 @ 20:54:24
j - Thursday, 4th of April 2019 @ 20:54:28
k - Thursday, 4th of April 2019 @ 20:54:31
l - Thursday, 4th of April 2019 @ 20:54:34
m - Thursday, 4th of April 2019 @ 20:54:37
n - Thursday, 4th of April 2019 @ 20:54:39
o - Thursday, 4th of April 2019 @ 20:54:42
p - Thursday, 4th of April 2019 @ 20:54:44
q - Thursday, 4th of April 2019 @ 20:55:47
r - Thursday, 4th of April 2019 @ 20:55:49
s - Thursday, 4th of April 2019 @ 20:55:51
t - Thursday, 4th of April 2019 @ 20:55:53
u - Thursday, 4th of April 2019 @ 20:55:55

...然后转到第3页，出现第2页的一些结果！

CHOOSE PAGE: 1 2 3 4 
Youre at page 3
Theres 26 articles

Showing 14 to 21

o - Thursday, 4th of April 2019 @ 20:54:42
p - Thursday, 4th of April 2019 @ 20:54:44
q - Thursday, 4th of April 2019 @ 20:55:47
r - Thursday, 4th of April 2019 @ 20:55:49
s - Thursday, 4th of April 2019 @ 20:55:51
t - Thursday, 4th of April 2019 @ 20:55:53
u - Thursday, 4th of April 2019 @ 20:55:55
v - Thursday, 4th of April 2019 @ 20:55:57
w - Thursday, 4th of April 2019 @ 20:56:00
x - Thursday, 4th of April 2019 @ 20:56:03
y - Thursday, 4th of April 2019 @ 20:56:05
z - Thursday, 4th of April 2019 @ 20:56:07

最后，我得到最后一页（第4页），而最后的最后结果来自第3页。

这里有代码...

<?php
$page = strip_tags($_GET['p']);
if(empty($page)){$page = "1";}

	$post_array = glob("post/*");
	$post_count = count($post_array);
	$page_num = ceil($post_count / 7);
	
	echo "CHOOSE PAGE: ";
	for($i = 1; $i<$page_num+1; $i++){
    echo "<a href=\"?p={$i}\">{$i}</a> ";
	}
	
	if($page>$page_num){
		echo "<br>error";
	} 
	elseif(!is_numeric($page)) {
		echo "<br>error";
	}
	else {echo "<br>Youre at page {$page}<br>";
	

	echo "Theres {$post_count} articles<br><br>";
	
	$start = $page * 7 - 7;
	$end = $page * 7;
	
	$post_array_sliced = array_slice($post_array, $start, $end);
	
	echo "Showing {$start} to {$end}<br><br>";
	
foreach ($post_array_sliced as $post){
		$post_name = pathinfo($post)['filename'];
		$post_date = filemtime($post);

		echo "{$post_name} - ".date('l, jS \of F Y @ H:i:s', $post_date)."<br>";
    }
}
?>

我认为这个问题是由我糟糕的逻辑技巧引起的。谁能纠正我，让我指向文档？

非常感谢您：）

Answer 1

array_slice不期望第一个和最后一个索引，但是期望第一个索引和长度（要提取的元素数）。所以你应该放：

array_slice（$ post_array，$ start，7）;

分页：逻辑吗？

1 个答案: