Question

我有一个简单的约会应用，可让用户注册未填写的时间段。用户将选择一个日期，并在数据库中查询当天可用的时隙。我将如何查询以获取仍可用的时隙？

models.py

class Appointment(models.Model):
    TIMESLOT_LIST = (
        (1, '10:00 – 11:00'),
        (2, '11:00 – 12:00'),
        (3, '12:00 – 13:00'),
        (4, '13:00 – 14:00'),
        (5, '14:00 – 15:00'),
        (6, '15:00 – 16:00'),
        (7, '16:00 – 17:00'),
        (8, '17:00 – 18:00'),
        (8, '18:00 – 19:00'),
    )

    date = models.DateField(default=date.today)
    timeslot = models.IntegerField(choices=TIMESLOT_LIST, null=True)

views.py

def make_appointment(request):
    all_appointments = Appointment.objects.values_list('timeslot')
    appointments = Appointment.objects.filter(user=request.user)
    data_input = request.GET.get('date')

    available_appointments = Appointment.objects.filter(
        date = data_input
    ).exclude(timeslot = appointments).values_list(
        'timeslot'
    ).order_by('timeslot')

    return TemplateResponse(
        request,
        'scheduling/appointment.html',
        {
            "appointments" : appointments,
            "all_appointments" : all_appointments,
            "data_input": data_input
        }
    )

Answer 1

您可以这样做来形成可用时间的新列表；

available_appointments = [
    (value, time) for value, time in TIMESLOT_LIST if value not in all_appointments
]

或者如果您想要一个元组；

tuple(
    (value, time) for value, time in TIMESLOT_LIST if value not in all_appointments
)

然后您可以在模板中提供这些选择，以供人们选择。

终端提供的示例；

>>> [(value, time) for value, time in TIMESLOT_LIST if value not in [1, 2, 3]]
[(4, '13:00 – 14:00'), (5, '14:00 – 15:00'), (6, '15:00 – 16:00'), (7, '16:00 – 17:00'), (8, '17:00 – 18:00'), (8, '18:00 – 19:00')]

Django：查询集以从模型字段中获取选择

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