Question

我遇到了一个奇怪的错误，在该错误中我使用请求库获取MIB文件的文本，而regex最初不想使用它。我正在尝试用任何内容替换空白行。

此代码可以找到我要正确替换的内容。

mib = r.text
blanklines = re.compile(r'\n+\s', re.DOTALL)
for line in blanklines.finditer(mib):
    ...

此代码未对字符串进行任何修改。

mib = r.text
blanklines = re.compile(r'\n+\s', re.DOTALL)
mib = blanklines.sub('\n', mib)

此代码正在完全按照我的要求修改字符串。

mib = r.text
with open('rtext.txt', 'w') as tfile:
    tfile.write(mib)

with open('rtext.txt','r') as tfile:
    mib = tfile.read()

blanklines = re.compile(r'\n+\s', re.DOTALL)
mib = blanklines.sub('\n', mib)

我不认为在周围使用这项工作很糟糕，但是我希望这里的人可以告诉我我做错了什么。我认为它必须与响应文本一起使用，因为它在写入文件然后再读回之后效果很好。

Answer 1

As commented the response had quite a few line breaks that were written as \r\n and I just overlooked them. Making one change mib = r.text.replace('\r', '') fixed the whole problem for me.

And I'm not necessarily trying to parse the entire MIB file so what I have working at this point is going to work for me. I'm really just checking a pcapng file for traps and if we don't have the OID info stored grabbing it from a repo at circitor.fr/Mibs.

Also if someone has a better repo than that I'd appreciate it because it can be pretty slow.

在Python中，来自请求模块的响应对象的文本与regex模块配合使用是否不好？

1 个答案: