Question

我正在开发一个播放音乐的discord.js机器人。这个想法是，用户可以键入“ X play”（X是机器人的前缀）来使机器人加入指挥官所在的语音通道。或者，用户可以键入“ X play [YouTube链接]”使用YTDL播放YouTube视频中的音频。到目前为止，该漫游器可以正常加入该频道。但是，当我附加一个链接时，会返回一个非常复杂的错误，我根本根本不理解。我已经参考过文档和帮助论坛，但是与我的问题无关。我已经附加了命令模块。

const Commando = require('discord.js-commando');
const YTDL = require('ytdl-core');

function Play(connection, message)
{
    var server = servers[message.guild.id];
    server.dispatcher = connection.playStream(YTDL(server.queue[0], {filter: "audioonly"}));
    server.queue.shift();
    server.dispatcher.on("end", function(){
        if(server.queue[0])
        {
            Play(connection, message);
        }
        else
        {
            connection.disconnect();
        }
    });

}

class JoinChannelCommand extends Commando.Command
{
    constructor(client)
    {
        super(client,{
            name: 'play',
            group: 'simple',
            memberName: 'play',
            description: 'Plays the audio from a youtube link'
        });
    }

    async run(message, args)
    {
        if(message.member.voiceChannel)
        {
            if(!message.guild.voiceConnection)
            {
                if(!servers[message.guild.id])
                {
                    servers[message.guild.id] = {queue: []}
                }
                message.member.voiceChannel.join()
                    .then(connection =>{
                        var server = servers[message.guild.id];
                        message.reply("Successfully joined!");
                        server.queue.push(args);
                        Play(connection, message);
                    })
            }
        }
        else
        {
            message.reply("ERROR: Not connected to voice channel");
        }
    }
}

module.exports = JoinChannelCommand;

当我键入“ X play”时，机器人将加入频道。当我键入“ X play [link]”时，该机器人会加入但不播放音乐。控制台返回：

(node:5136) UnhandledPromiseRejectionWarning: TypeError [ERR_INVALID_ARG_TYPE]: The "file" argument must be of type string. Received type object
    at validateString (internal/validators.js:125:11)
    at normalizeSpawnArguments (child_process.js:414:3)
    at Object.spawn (child_process.js:553:16)
    at new FfmpegProcess (C:\My Discord Bots\XyloBot\node_modules\prism-media\src\transcoders\ffmpeg\FfmpegProcess.js:14:33)
    at FfmpegTranscoder.transcode (C:\My Discord Bots\XyloBot\node_modules\prism-media\src\transcoders\ffmpeg\Ffmpeg.js:34:18)
    at MediaTranscoder.transcode (C:\My Discord Bots\XyloBot\node_modules\prism-media\src\transcoders\MediaTranscoder.js:27:31)
    at Prism.transcode (C:\My Discord Bots\XyloBot\node_modules\prism-media\src\Prism.js:13:28)
    at AudioPlayer.playUnknownStream (C:\My Discord Bots\XyloBot\node_modules\discord.js\src\client\voice\player\AudioPlayer.js:97:35)
    at VoiceConnection.playStream (C:\My Discord Bots\XyloBot\node_modules\discord.js\src\client\voice\VoiceConnection.js:478:24)
    at Play (C:\My Discord Bots\XyloBot\commands\music\join.js:7:36)
(node:5136) UnhandledPromiseRejectionWarning: Unhandled promise rejection. This error originated either by throwing inside of an async function without a catch block, or by rejecting a promise which was not handled with .catch(). (rejection id: 1)
(node:5136) [DEP0018] DeprecationWarning: Unhandled promise rejections are deprecated. In the future, promise rejections that are not handled will terminate the Node.js process with a non-zero exit code.

很长一段代码等的道歉，但是这远远超出了我的能力范围。任何帮助都将受到赞赏。

Discord.js机器人-音乐函数：“无效的参数类型”-无法识别问题

0 个答案: