为什么discord.py-rewrite bot.loop.create_task(my_background_task())执行一次却不重复

时间:2019-04-05 15:53:58

标签: discord.py-rewrite

使用Discord.py-rewrite,我们如何诊断my_background_task以找出其打印语句每3秒不打印一次的原因?

详细信息: 我观察到的问题是在日志中一次打印了“ print('inside loop')”,而不是预期的“每三秒钟”。我没有发现某个地方有例外吗?

注意:我确实在日志中看到print(f'Logged in as {bot.user.name} - {bot.user.id}'),所以on_ready似乎有用,所以该方法不能怪。

我尝试了以下示例:https://github.com/Rapptz/discord.py/blob/async/examples/background_task.py 但是我没有使用它的client = discord.Client()语句,因为我认为可以使用类似于此处https://stackoverflow.com/a/53136140/6200445

的“ bot”来实现相同的目的
import asyncio
import discord
from discord.ext import commands

token = open("token.txt", "r").read()


def get_prefix(client, message):

    prefixes = ['=', '==']    

    if not message.guild:
        prefixes = ['==']   # Only allow '==' as a prefix when in DMs, this is optional

    # Allow users to @mention the bot instead of using a prefix when using a command. Also optional
    # Do `return prefixes` if u don't want to allow mentions instead of prefix.
    return commands.when_mentioned_or(*prefixes)(client, message)


bot = commands.Bot(                         # Create a new bot
    command_prefix=get_prefix,              # Set the prefix
    description='A bot for doing cool things. Commands list:',  # description for the bot
    case_insensitive=True                   # Make the commands case insensitive
)

# case_insensitive=True is used as the commands are case sensitive by default

cogs = ['cogs.basic','cogs.embed']


@bot.event
async def on_ready():                                       # Do this when the bot is logged in
    print(f'Logged in as {bot.user.name} - {bot.user.id}')  # Print the name and ID of the bot logged in.
    for cog in cogs:
        bot.load_extension(cog)
    return


async def my_background_task():
    await bot.wait_until_ready()
    print('inside loop') # This prints one time. How to make it print every 3 seconds?
    counter = 0
    while not bot.is_closed:
        counter += 1
        await bot.send_message(channel, counter)
        await channel.send(counter)
        await asyncio.sleep(3) # task runs every 3 seconds

bot.loop.create_task(my_background_task())
bot.run(token)
[]

2 个答案:

答案 0 :(得分:2)

从粗略的检查来看,似乎您的问题是您只是调用了一次。您的方法 my_background_task不会每三秒钟调用一次。每三秒钟调用一次send_message方法。对于预期的行为,请将print语句放入while循环内。

答案 1 :(得分:0)