我试图通过WinHttpRequest从以下网址导入JSON格式的信息： https://bet.hkjc.com/football/getJSON.aspx?jsontype=odds_allodds.aspx&matchid=default
Sub test()
Dim xmlhttp As Object
Dim strUrl As String: strUrl = "https://bet.hkjc.com/football/getJSON.aspx?jsontype=odds_allodds.aspx&matchid=default"
Dim objRequest As Object
Set objRequest = CreateObject("WinHttp.WinHttpRequest.5.1")
With objRequest
.Open "GET", strUrl, False
.send
End With
Debug.Print objRequest.responseText
End Sub
但是，它只显示了与Url类似的内容，但显示了很多乱码。
我想知道如何解决这个问题。 如果我使用其他网址，代码可以正常工作。
答案 0 :(得分：0)
我认为该页面已采取了防止漫游器的措施，如果怀疑您是漫游器，则会引发挑战，需要运行javascript。如果该命令成功运行，则会向XHR请求发出标头中的质询信息，并且如果您使用的是浏览器，则会导致您的内容正确更新以显示期望值。
我第一次运行GET请求时，得到了预期的json响应，此后，我得到了以下信息：
<HTML>
<head>
<script>
Challenge=649275;
ChallengeId=473313563;
GenericErrorMessageCookies="Cookies must be enabled in order to view this page.";
</script>
<script>
function test(var1)
{
var var_str=""+Challenge;
var var_arr=var_str.split("");
var LastDig=var_arr.reverse()[0];
var minDig=var_arr.sort()[0];
var subvar1 = (2 * (var_arr[2]))+(var_arr[1]*1);
var subvar2 = (2 * var_arr[2])+var_arr[1];
var my_pow=Math.pow(((var_arr[0]*1)+2),var_arr[1]);
var x=(var1*3+subvar1)*1;
var y=Math.cos(Math.PI*subvar2);
var answer=x*y;
answer-=my_pow*1;
answer+=(minDig*1)-(LastDig*1);
answer=answer+subvar2;
return answer;
}
</script>
<script>
client = null;
if (window.XMLHttpRequest)
{
var client=new XMLHttpRequest();
}
else
{
if (window.ActiveXObject)
{
client = new ActiveXObject('MSXML2.XMLHTTP.3.0');
};
}
if (!((!!client)&&(!!Math.pow)&&(!!Math.cos)&&(!![].sort)&&(!![].reverse)))
{
document.write("Not all needed JavaScript methods are supported.<BR>");
}
else
{
client.onreadystatechange = function()
{
if(client.readyState == 4)
{
var MyCookie=client.getResponseHeader("X-AA-Cookie-Value");
if ((MyCookie == null) || (MyCookie==""))
{
document.write(client.responseText);
return;
}
var cookieName = MyCookie.split('=')[0];
if (document.cookie.indexOf(cookieName)==-1)
{
document.write(GenericErrorMessageCookies);
return;
}
window.location.reload(true);
}
};
y=test(Challenge);
client.open("POST",window.location,true);
client.setRequestHeader('X-AA-Challenge-ID', ChallengeId);
client.setRequestHeader('X-AA-Challenge-Result',y);
client.setRequestHeader('X-AA-Challenge',Challenge);
client.setRequestHeader('Content-Type' , 'text/plain');
client.send();
}
</script>
</head>
<body>
您是否模仿javascript的功能并将其作为新的XHR传递（不确定）（不确定）。
您还可以尝试使用浏览器自动化功能，例如IE通过Microsoft Internet Controls或Chrome / FF等通过Selenium Basic，以查看是否让javascript在页面上运行可以解决此问题。
我开始考虑尝试解决这个问题。目前，我一直在获取json响应，因此尚未完全测试底部。我希望有些分钟 *我们关心吗？错误的余地，仅仅是因为Math.PI给出了3.141592653589793，而Application.PI给出了{ {1}}
3.14159265358979使用Microsoft Internet Controls进行标准IE自动化会导致“另存为/打开对话框”提示。
使用硒可以避免出现此提示，并从pre元素中获取数据。使用硒可以使您受益于隐式等待，该等待使页面可以完成发出的所有挑战。您可以使用明确的等待条件来增加等待时间。
Option Explicit
Public Sub GetInfo()
Dim json As Object, s As String, re As Object, ws As Worksheet
Dim pattern1 As String, pattern2 As String, challenge As Long, challengeId As Long
Const URL As String = "https://bet.hkjc.com/football/getJSON.aspx?jsontype=odds_allodds.aspx&matchid=default"
pattern1 = "Challenge=(\d+);"
pattern2 = "ChallengeId=(\d+);"
Set re = CreateObject("vbscript.regexp")
Set ws = ThisWorkbook.Worksheets("Sheet1")
With CreateObject("MSXML2.XMLHTTP")
.Open "GET", URL, False
.setRequestHeader "User-Agent", "Mozilla/5.0"
.send
s = .responseText
On Error Resume Next
Set json = JsonConverter.ParseJson(s)
On Error GoTo 0
If Not json Is Nothing Then
Debug.Print "No challenge issued"
Debug.Print .responseText
Else
On Error GoTo errhand
challenge = GetId(re, s, pattern1)
If challenge = 999 Then Exit Sub 'should really use more unlikely value.
challengeId = GetId(re, s, pattern2)
.Open "POST", URL, False
.setRequestHeader "X-AA-Challenge-ID", challengeId
.setRequestHeader "X-AA-Challenge-Result", CLng(GetAnswer(challenge))
.setRequestHeader "X-AA-Challenge", challenge
.setRequestHeader "Content-Type", "text/plain"
.send ""
Debug.Print .Status, .responseText
If .Status = 200 Then
.Open "GET", URL, False
.setRequestHeader "User-Agent", "Mozilla/5.0"
.send
s = .responseText
Debug.Print s
End If
End If
End With
Exit Sub
errhand:
Debug.Print Err.Number, Err.Description
End Sub
Public Function GetId(ByVal re As Object, ByVal s As String, ByVal pattern As String) As Long
With re
.Global = True
.MultiLine = True
.IgnoreCase = False
.pattern = pattern
If .TEST(s) Then
GetId = .Execute(s)(0).SubMatches(0)
Else
GetId = 999 '<probably should use a more unlikely number here!
End If
End With
End Function
Public Function GetAnswer(ByVal challenge As Long) As String 'var1 'challenge
Dim var_str As String, var_arr() As Long, LastDig As Long, minDig As Long
Dim i As Long
var_str = Chr$(34) & challenge & Chr$(34)
ReDim var_arr(0 To Len(var_str) - 3)
For i = 2 To Len(var_str) - 1
var_arr(i - 2) = CLng(Mid$(var_str, i, 1))
Next i
LastDig = var_arr(UBound(var_arr))
minDig = Application.Min(var_arr)
Dim my_pow As Long, x As Long, y As Long, answer As Variant
Dim subvar1 As Long, subvar2 As String
subvar1 = 2 * Application.Small(var_arr, 3) + Application.Small(var_arr, 2)
subvar2 = CStr(2 * Application.Small(var_arr, 3)) & CStr(Application.Small(var_arr, 2))
my_pow = (minDig + 2) ^ Application.Small(var_arr, 2)
x = challenge * 3 + (subvar1 * 1)
y = Evaluate("=COS(PI()* " & CLng(subvar2) & ")")
answer = x * y
answer = answer - my_pow
answer = answer + minDig - LastDig
answer = CStr(answer) & subvar2
GetAnswer = answer
End Function
请注意，我正在使用json parser。从该链接添加.bas之后，您需要转到VBE>工具>引用>添加对Microsoft脚本运行时的引用。