Question

我这样排列，现在我想对具有相同发起人名称的费用进行总计。

并使用该数组创建一个新数组，因此这里有3个cima haves，我需要其中的一个数组，其中fee_potetial是发起者为cima haves的所有其他数组的总和。

$formEntries返回如下值：

Array
(
    [0] => Array
        (
            [entry_id] => 54
            [0] => 1
            [fee_potential] => 100
            [originator] => cima haves

        )

    [1] => Array
        (
            [entry_id] => 55
            [0] => 1
            [fee_potential] => 600
            [originator] => steve

        )

    [2] => Array
        (
            [entry_id] => 56
            [0] => 1
            [fee_potential] => 500
            [originator] => cima haves

        )

    [3] => Array
        (
            [entry_id] => 57
            [0] => 1
            [fee_potential] => 500
            [originator] =>  cima haves

        )

)

这是我尝试隔离的代码：

$originator = array_column($formEntries, 'originator');
$originator = array_unique($originator);
$array_filter = array_filter($formEntries, function ($key, $value) use ($originator) {
    return in_array($value, array_keys($originator));
}, ARRAY_FILTER_USE_BOTH);

我需要输出[fee_potential] => 1100是总和

Array
    (
        [0] => Array
            (
                [entry_id] => 54
                [0] => 1
                [fee_potential] => 1100
                [originator] => cima haves

            )

        [1] => Array
            (
                [entry_id] => 55
                [0] => 1
                [fee_potential] => 600
                [originator] => steve

            )
    )

Answer 1

一个简单的foreach循环会非常简单

$totals = [];

foreach( $formEntries as $entry) {
    if( isset($totals[$entry['originator']]){
        $totals[$entry['originator']]['fee_potential'] += $entry['fee_potential'];
    } else {
        $totals[$entry['originator']]['fee_potential'] = $entry['fee_potential'];
    }
}

Answer 2

只需尝试遍历所有此类元素

$final_arr = array();
foreach($formEntries as $value){
    if(isset($final_arr[$value['originator']])){
        $final_arr[$value['originator']]['fee_potential'] += $value['fee_potential'];
    }
    else{
        $final_arr[$value['originator']] = $value;
    }

}

它将检查最终数组中是否已存在originator。如果是这样，它将对值求和，否则它将与fee_potential一起分配该数组。

Answer 3

尝试使用此代码，即可正常运行。

$result = array();
foreach($formEntries as $key => $v){
   if(in_array($v['originator'], array_column($result, 'originator'))){
      $result[array_search($v['originator'], array_column($result, 'originator'))]['fee_potential'] += $v['fee_potential'];
   }else{
      $result[$key] = $v;
   }
}

结果：-

Array
(
    [0] => Array
        (
            [entry_id] => 54
            [0] => 1
            [fee_potential] => 1100
            [originator] => cima haves

        )

    [1] => Array
        (
            [entry_id] => 55
            [0] => 1
            [fee_potential] => 600
            [originator] => steve

        )
)

重复键值php的错误总数

3 个答案: