输入:- 在这里,我有重复natraj的数组对象,因此我需要像给定示例一样附加一些计数。
var aa= [
{name:'natraj'},
{name:'ajai'},
{name:'natraj'},
{name:'ajai'},
{name:'barath'},
{name:'ajai'},
{name:'barath'},
{name:'natraj'},
]
输出:-
[
{name:'natraj'},
{name:'ajai'},
{name:'natraj_1'},
{name:'ajai_1'},
{name:'barath'},
{name:'ajai_2'},
{name:'barath_1'},
{name:'natraj_2'},
]
答案 0 :(得分:5)
保持连续计数:
var aa = [{name:'natraj'},{name:'ajai'},{name:'natraj'},{name:'ajai'},{name:'barath'},{name:'ajai'},{name:'barath'},{name:'natraj'},]
let counts = {}
aa.forEach(o => {
if (counts[o.name]) {
o.name += `_${counts[o.name]++}`
} else {
counts[o.name] = 1
}
});
console.log(aa)