我正在尝试从php脚本创建一个pdf。我有JasperReports& PHP / JavaBridge启动并运行,它可以在发送字符串时生成pdf文件&整数作为参数。
我使用了Jasper Reports and PHP&的指南。 Bullet-Proof Jasper Reports and PHP帮助设置PHP / JavaBridge和Jasper报告。
这就是我的php脚本目前的样子(非常类似于前面提到的指南中的示例):
<?php
/**
* see if the java extension was loaded.
*/
function checkJavaExtension()
{
if(!extension_loaded('java'))
{
$sapi_type = php_sapi_name();
$port = (isset($_SERVER['SERVER_PORT']) && (($_SERVER['SERVER_PORT'])>1024)) ? $_SERVER['SERVER_PORT'] : '8080';
if ($sapi_type == "cgi" || $sapi_type == "cgi-fcgi" || $sapi_type == "cli")
{
if(!(PHP_SHLIB_SUFFIX=="so" && @dl('java.so'))&&!(PHP_SHLIB_SUFFIX=="dll" && @dl('php_java.dll'))&&!(@include_once("java/Java.inc"))&&!(require_once("http://127.0.0.1:$port/java/Java.inc")))
{
return "java extension not installed.";
}
}
else
{
if(!(@include_once("java/Java.inc")))
{
require_once("http://127.0.0.1:$port/java/Java.inc");
}
}
}
if(!function_exists("java_get_server_name"))
{
return "The loaded java extension is not the PHP/Java Bridge";
}
return true;
}
/**
* convert a php value to a java one...
* @param string $value
* @param string $className
* @returns boolean success
*/
function convertValue($value, $className)
{
// if we are a string, just use the normal conversion
// methods from the java extension...
try
{
if ($className == 'java.lang.String')
{
$temp = new Java('java.lang.String', $value);
return $temp;
}
else if ($className == 'java.lang.Boolean' ||
$className == 'java.lang.Integer' ||
$className == 'java.lang.Long' ||
$className == 'java.lang.Short' ||
$className == 'java.lang.Double' ||
$className == 'java.math.BigDecimal')
{
$temp = new Java($className, $value);
return $temp;
}
else if ($className == 'java.sql.Timestamp' ||
$className == 'java.sql.Time')
{
$temp = new Java($className);
$javaObject = $temp->valueOf($value);
return $javaObject;
}
}
catch (Exception $err)
{
echo ( 'unable to convert value, ' . $value .
' could not be converted to ' . $className);
return false;
}
echo ( 'unable to convert value, class name '.$className.
' not recognised');
return false;
}
if (true == checkJavaExtension()) {
echo 'java extension is loaded!!';
}
$compileManager = new JavaClass("net.sf.jasperreports.engine.JasperCompileManager");
$report = $compileManager->compileReport(realpath("test.jrxml"));
$fillManager = new JavaClass("net.sf.jasperreports.engine.JasperFillManager");
$params = new Java("java.util.HashMap");
$params->put("text", "This is a text");
$params->put("report_id", 2);
$emptyDataSource = new Java("net.sf.jasperreports.engine.JREmptyDataSource");
$jasperPrint = $fillManager->fillReport($report, $params, $emptyDataSource);
$outputPath = realpath(".")."/"."output.pdf";
$exportManager = new JavaClass("net.sf.jasperreports.engine.JasperExportManager");
$exportManager->exportReportToPdfFile($jasperPrint, $outputPath);
header("Content-type: application/pdf");
readfile($outputPath);
unlink($outputPath);
?>
上面的代码可行,但我想使用PHP数组作为我的jrxml文件的参数。对此最好的解决方案是什么?
我想我可能要创建一个java.util.List类,将我的php数据中的数据设置为列表项,并将其作为参数发送到我的jrxml文件,但我无法得到这个上班。
另一方面,这可能是非常错误的,因为这对我来说都很新鲜:\我感谢所有帮助! :)
答案 0 :(得分:0)
我不确定我理解,但如果您有一系列值,例如{id =&gt; 1,name =&gt; 'fubar',某事=&gt; 'blala'。试试这个:
$map = new Java("java.util.HashMap");
foreach ($array as $key=>$value){
$map->put($key,$value);
}
$Jfm = new Java("net.sf.jasperreports.engine.JasperFillManager");
$this->FillReport = $Jfm->fillReport($this->CompileReport, $map, $this->DbConnect);