输出

Question

我有以下示例数据：

defaultsChanged

现在我有了给定的输入值，可以根据传递的输入值在序列表中进行搜索。

例如：

-- Table 1: A_Series

create table A_Series
(
    series varchar(10)
);
insert into A_Series values('A101'),('A102'),('A103'),('A104');  

-- Table 1: B_Series

create table B_Series
(
    series varchar(10)
);
insert into B_Series values('B101'),('B102'),('B103'),('B104');

我要生成DECLARE @input varchar(255) = 'A101,B102,A104'语句，如下所示：

预期结果：

SELECT

上述预期结果的解释：如果给定的输入值是select series from A_Series where series in ('A101','A104') union select series from B_Series where series in ('B102')系列，那么我们需要在A表中进行搜索，如果值是A_Series系列，则使用B子句中的相关系列在B_Series表中进行搜索。

我的尝试：

WHERE

无法创建DECLARE @input varchar(255) = 'A101,B102,A104' DECLARE @query varchar(max) = '' DECLARE @Series_Where varchar(max) = '' SET @query = ' SELECT STUFF((SELECT '' SELECT * FROM [''+cast(name AS varchar(200))+''] UNION ALL '' AS [text()] FROM sys.tables t WHERE SUBSTRING(t.name,1,6) IN (SELECT SUBSTRING(Item,3,2)+''_SDR'' FROM udf_Split('''+@input+''','','')) FOR XML PATH('''') ), 1, 1, '''')'; PRINT(@query);，如预期结果查询中所示。

Answer 1

我发现在执行动态SQL时，while循环最适合构建SQL。您可以轻松地将其分解成小块。

EG

    SET NOCOUNT ON;
DECLARE @input varchar(255) = 'A101,B102,A104'
DECLARE @InputT TABLE(Val varchar(255));
DECLARE @SQL VARCHAR(8000)='';
DECLARE @SQL_INNER VARCHAR(255)='';

INSERT @InputT SELECT VALUE FROM string_split(@input, ',');

DECLARE @i INT
DECLARE @search VARCHAR(255);
SET @i = ASCII('A');
WHILE @i <= ASCII('B') -- Set Max Table here'
BEGIN

    SELECT @search = COALESCE(@search + ', ', '') + Val FROM @InputT WHERE Val like CHAR(@i)+'%';

    SELECT @SQL_INNER = 'select series 
from ' + CHAR(@i) + '_Series
    where series in (''' + REPLACE(@search, ',', ''',''') + ''')'

    IF @i >  ASCII('A') SET @SQL += '
UNION ALL
'
    SET @SQL += @SQL_INNER;

    SET @i +=1;
    set @search = NULL;

END
PRINT @SQL

注意-我正在使用String_Split（）加载表，但是其他任何csv-> rows方法也可以使用。 COALESCE（）用于构建Search，REPLACE（）用于添加多余的单引号。

Answer 2

如果您实际上只是想要动态创建的查询的结果，则也无需使用动态SQL：

declare @A_Series table (series varchar(10));
declare @B_Series table (series varchar(10));
insert into @A_Series values('A101'),('A102'),('A103'),('A104');  
insert into @B_Series values('B101'),('B102'),('B103'),('B104'); 

declare @input varchar(255) = 'A101,B102,A104';

with s as
(
    select item
    from dbo.fn_StringSplit4k(@input,',',null) as s
)
select a.series
from @A_Series as a
    join s
        on s.item = a.series
union all
select b.series
from @b_Series as b
    join s
        on s.item = b.series;

输出

series
A101
A104
B102

字符串拆分功能

这是Jeff Moden's function的修改版本：

CREATE function [dbo].[fn_StringSplit4k]
(
     @str nvarchar(4000) = ' '              -- String to split.
    ,@delimiter as nvarchar(1) = ','        -- Delimiting value to split on.
    ,@num as int = null                     -- Which value to return.
)
returns table
as
return
                    -- Start tally table with 10 rows.
    with n(n)   as (select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1 union all select 1)

                    -- Select the same number of rows as characters in @str as incremental row numbers.
                    -- Cross joins increase exponentially to a max possible 10,000 rows to cover largest @str length.
        ,t(t)   as (select top (select len(isnull(@str,'')) a) row_number() over (order by (select null)) from n n1,n n2,n n3,n n4)

                    -- Return the position of every value that follows the specified delimiter.
        ,s(s)   as (select 1 union all select t+1 from t where substring(isnull(@str,''),t,1) = @delimiter)

                    -- Return the start and length of every value, to use in the SUBSTRING function.
                    -- ISNULL/NULLIF combo handles the last value where there is no delimiter at the end of the string.
        ,l(s,l) as (select s,isnull(nullif(charindex(@delimiter,isnull(@str,''),s),0)-s,4000) from s)

    select rn
          ,item
    from(select row_number() over(order by s) as rn
                ,substring(@str,s,l) as item
        from l
        ) a
    where rn = @num
        or @num is null;

带where子句的动态选择查询

2 个答案:

输出

字符串拆分功能