pygame按钮无法运行

时间:2019-04-05 08:54:07

标签: python loops button pygame

(英语不是我的母语,所以请原谅任何错误。) (谢谢大家!)

当我单击按钮“ 1”时,将显示BE01,但如果不单击,将返回scene01Img。

我尝试在def BE01():中使用gameExit = true,但是不起作用。

pygame.init()

clock = pygame.time.Clock()

def button(msg,x,y,w,h,ic,ac,action=None):
    mouse = pygame.mouse.get_pos()
    click = pygame.mouse.get_pressed()
    if x+w > mouse[0] > x and y+h > mouse[1] > y:
        pygame.draw.rect(gameDisplay, ac,(x,y,w,h))

        if click[0] == 1 and action != None:
            action()         
    else:
        pygame.draw.rect(gameDisplay, ic,(x,y,w,h))

    smallText = pygame.font.SysFont("comicsansms",20)
    textSurf, textRect = text_objects(msg, smallText)
    textRect.center = ( (x+(w/2)), (y+(h/2)) )
    gameDisplay.blit(textSurf, textRect)

def BE01():
    gameDisplay.fill(white)
    gameDisplay.blit(BE01Img,(0,0))
    button("BACK",350,450,100,50,black,gray,game_intro)

def game_intro():

    intro = True

    while intro:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                quit()

        gameDisplay.fill(white)
        gameDisplay.blit(introImg,(0,0))
        button("START",350,450,100,50,black,gray,game_loop)

        pygame.display.update()
        clock.tick(15)    

def quitgame():
    pygame.quit()
    quit()   

def game_loop():
    gameExit = False

    while not gameExit:

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                quit()

        gameDisplay.fill(white)
        gameDisplay.blit(scene01Img,(0,0))
        button("1",200,450,100,50,black,gray,BE01)

        pygame.display.update()
        clock.tick(60)

game_intro()
game_loop()
pygame.quit()
quit()

单击按钮“ 1”后,将出现BE01并运行另一个程序,不应出现scene01。

1 个答案:

答案 0 :(得分:0)

每个场景都应该有自己的loop,并且当您按下按钮时,您应该转到新的loop

如果要在一个循环中更改元素,则将旧元素放在某个函数(即draw_intro)中,将新元素放在另一个函数(即draw_other)中-开始时使用{{1 }}循环播放,当您按下按钮时,将此功能替换为draw_intro

在Python中,您可以将函数名称(不带draw_other)分配给变量

()

,然后使用此名称(使用show = print

()

您可以对show("Hello World") draw_intro执行相同的操作。

在游戏内循环(在draw_other之前),您可以设置

while

并在global draw draw = draw_intro

中使用它
while

当您按下按钮时,它应该代替功能

draw()

这里有完整的工作代码-我只删除了所有draw = draw_other 即可轻松运行它而没有图像。

blit(image)

编辑:

如果您以前没有使用过import pygame black = (0,0,0) white = (255,255,255) gray = (128,128,128) red = (255,0,0) pygame.init() gameDisplay = pygame.display.set_mode( (800,600)) clock = pygame.time.Clock() def button(msg,x,y,w,h,ic,ac,action=None): mouse = pygame.mouse.get_pos() click = pygame.mouse.get_pressed() if x+w > mouse[0] > x and y+h > mouse[1] > y: pygame.draw.rect(gameDisplay, ac, (x,y,w,h)) if click[0] == 1 and action != None: action() else: pygame.draw.rect(gameDisplay, ic, (x,y,w,h)) smallText = pygame.font.SysFont("comicsansms",20) textSurf = smallText.render(msg, True, red) textRect = textSurf.get_rect() textRect.center = ( (x+(w/2)), (y+(h/2)) ) gameDisplay.blit(textSurf, textRect) def change_draw(new_draw): global draw draw = new_draw def draw_BE01(): gameDisplay.fill(white) #gameDisplay.blit(BE01Img,(0,0)) button("BACK",350,450,100,50,black,gray,lambda:change_draw(draw_intro)) def draw_intro(): gameDisplay.fill(white) #gameDisplay.blit(introImg,(0,0)) button("START",350,450,100,50,black,gray,lambda:change_draw(draw_other)) def draw_other(): gameDisplay.fill(white) #gameDisplay.blit(scene01Img,(0,0)) button("1",200,450,100,50,black,gray,lambda:change_draw(draw_BE01)) def quitgame(): pygame.quit() quit() def game_loop(): global draw draw = draw_intro gameExit = False while not gameExit: for event in pygame.event.get(): if event.type == pygame.QUIT: pygame.quit() quit() draw() pygame.display.update() clock.tick(60) game_loop() pygame.quit() quit() ,那么可以不用lamda来使用它,但是您将需要lambdachange_draw_to_introchange_draw_to_other而不是单个change_draw_to_BE01

change_draw