Question

运行此命令：

GITIGNORE_CONTENTS = $(shell while read -r line; do printf "$$line "; done < "$(.gitignore)")

all:
    echo $(GITIGNORE_CONTENTS)

变量GITIGNORE_CONTENTS的内容是我的.gitignore文件上的忽略模式的扩展版本，即myfile.txt而非*.txt

我使用此解决方案是因为问题Create a variable in a makefile by reading contents of another file的解决方案均无效。

此解决方案在make规则内工作以打印文件名，但不将其放在变量内：

all:
    while read -r line; do \
        printf "$$line "; \
    done < ".gitignore"
    echo $(GITIGNORE_CONTENTS)

Answer 1

这是Shell的通配符扩展问题，而不是make的问题。考虑一下，

GITIGNORE_CONTENTS:=$(shell cat .gitignore)

.PHONY: all
all:
    echo "$(GITIGNORE_CONTENTS)"
    # or alternatively:
    #/bin/echo $(GITIGNORE_CONTENTS)

Answer 2

运行此命令：

GITIGNORE_CONTENTS = $(shell while read -r line; do printf "$$line "; done < ".gitignore")

all:
    echo "$(GITIGNORE_CONTENTS)"

带有以下.gitignore文件：

*.txt
*.var
# Comment
*.xml
*.html

它正确输出：

echo "*.txt *.var # Comment *.xml *.html "
*.txt *.var # Comment *.xml *.html

如何阻止Makefile扩展我的shell输出？

2 个答案: