Question

我需要找到每个部门的最高平均工资。然后，我只需要返回具有最高平均薪水且保留两位小数的部门（NAME和DEPT_MAX_AVG_SALARY）（即，可能有多个具有相同的最高平均薪水的小数，这很好，我们需要所有相等的部门该金额）。

 SELECT p.DEPARTMENT_ID, d.NAME, cast(AVG(p.SALARY) as decimal(18,2)) as AVERAGE
  FROM PROFESSOR p 
  INNER JOIN DEPARTMENT d   ON p.DEPARTMENT_ID = d.ID
  GROUP BY p.DEPARTMENT_ID, d.NAME

  HAVING AVG(p.SALARY) =
  (
  SELECT TOP 1 AVG(a.SALARY) as MAXAVERAGE
  FROM PROFESSOR a 
  INNER JOIN DEPARTMENT b
  ON a.DEPARTMENT_ID = b.ID
  GROUP BY a.DEPARTMENT_ID
  ORDER BY MAXAVERAGE DESC
  )
  ORDER BY AVERAGE DESC

有更好的方法吗？

Answer 1

select max(d.avg) from (
    select avg(salary) "avg" from professor group by department  
) as d

这显然是简化版本，但是逻辑在那里。您从派生表中计算出的平均值中选择最大值，该平均值按部门分组。

Answer 2

我建议您尝试使用WITH TIES和ORDER BY：

Select TOP 1 WITH TIES
 d.NAME as dep_name
,AVG(cast(p.SALARY as decimal(18,2)) as avg_dep_salary
From PROFESSOR p
Inner join DEPARTMENT d on p.DEPARTMENT_ID = d.ID
Group by
 d.ID
,d.NAME
Order by avg_dep_salary desc

Answer 3

TOP (1) WITH TIES是必经之路。但是我认为查询看起来像这样：

select top (1) with ties d.id, d.NAME as dep_name,
       cast(avg(p.SALARY) as decimal(18, 2)) as avg_dep_salary
from PROFESSOR p Inner join
     DEPARTMENT d 
     on p.DEPARTMENT_ID = d.ID
group by d.ID, d.NAME
order by avg_dep_salary desc;

在计算平均值之后，强制转换值很重要。如果salary是整数，那么您可能需要：

       cast(avg(p.SALARY * 1.0) as decimal(18, 2)) as avg_dep_salary

查找最大平均薪水并打印（即使有倍数），我缺少小数

3 个答案: