我需要一个批处理脚本来随机选择文件夹中的X个文件并将它们移动到另一个文件夹。如何编写可以执行此操作的Windows批处理脚本?
答案 0 :(得分:8)
(我假设您的 X 事先已知 - 由以下代码中的变量$x
表示)。
由于您没有对PowerShell解决方案产生负面影响:
Get-ChildItem SomeFolder | Get-Random -Count $x | Move-Item -Destination SomeOtherFolder
或更短:
gci somefolder | random -c $x | mi -dest someotherfolder
答案 1 :(得分:3)
以下批处理代码将执行此操作。请注意,您需要使用以下命令行启动cmd:
cmd /v:on
启用延迟环境变量扩展。另请注意,它将从0到32767选择随机数量的文件 - 您可能需要修改此部分以满足您的要求!
@ECHO OFF
SET SrcCount=0
SET SrcMax=%RANDOM%
FOR %F IN (C:\temp\source\*.*) DO IF !SrcCount! LSS %SrcMax% (
SET /A SrcCount += 1
ECHO !SrcCount! COPY %F C:\temp\output
COPY %F C:\temp\output
)
答案 2 :(得分:2)
@echo off & setlocal
set "workDir=C:\source\folder"
::Read the %random%, two times is'nt a mistake! Why? Ask Bill.
::In fact at the first time %random% is nearly the same.
@set /a "rdm=%random%"
set /a "rdm=%random%"
::Push to your path.
pushd "%workDir%"
::Count all files in your path. (dir with /b shows only the filenames)
set /a "counter=0"
for /f "delims=" %%i in ('dir /b ^|find "."') do call :sub1
::This function gives a value from 1 to upper bound of files
set /a "rdNum=(%rdm%*%counter%/32767)+1"
::Start a random file
set /a "counter=0"
for /f "delims=" %%i in ('dir /b ^|find "."') do set "fileName=%%i" &call :sub2
::Pop back from your path.
popd "%workDir%"
goto :eof
:: end of main
:: start of sub1
:sub1
::For each found file set counter + 1.
set /a "counter+=1"
goto :eof
:: end of sub1
:: start of sub2
:sub2
::1st: count again,
::2nd: if counted number equals random number then start the file.
set /a "counter+=1"
if %counter%==%rdNum% (
:: OUTPUT ALERT BOX with FILENAME
MSG * "%fileName%"
)
goto :eof
:: end of sub2
答案 3 :(得分:0)
@echo off
setlocal EnableDelayedExpansion
cd \particular\folder
set n=0
for %%f in (*.*) do (
set /A n+=1
set "file[!n!]=%%f"
)
set /A "rand=(n*%random%)/32768+1"
copy "!file[%rand%]!" \different\folder
来自Need to create a batch file to select one random file from a folder and copy to another folder