Question

我正在尝试解析具有以下结构的xml文件：

<?xml version="1.0" encoding="utf-8"?>
<root>
    <tag1 id="92">
        <tag11>Some text for parsing</tag11>
        <tag12 src="http://some_valid_url_with_image" />
    </tag1>
    <tag2 attr1="111111" attr2="222222" attr2="333333">
        <tag21>Some text for parsing 2</tag21>
        <tag22 attr1="4444444">Some text for parsing 3</tag22>
        <tag23 attr1="5555555">Some text for parsing 4</tag23>
        <tag24 attr1="32">Some text for parsing 5</tag24>
        <tag25 attr1="21">Some text for parsing 6</tag25>
    </tag2>
</root>

我将XMLPullParser与开关盒结构和我自己的适配器一起使用：

public class XMLParse extends AppCompatActivity {
    String tagname = "";
    String tagtext = "";
    String tag11 = "tag11";
    String tag12 = "tag12";
    String tag12VALUE = "";

    public Bitmap myBitmap;

    private List<SomeItem> items = new ArrayList();
    protected void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_some);
        listView = findViewById(R.id.listView);
        IV = findViewById(R.id.iconsrc);
        try {
            XmlPullParser parser = getResources().getXml(R.xml.myxml);

            while (parser.next() != XmlPullParser.END_DOCUMENT) {

                switch (parser.getEventType()){
                    case XmlPullParser.TEXT :
                        tagtext = parser.getText();
                        if (tagname != null && tagname.equals(tag11)) {
                            items.add(new SomeItem(tagtext, IV));
                        }
                        if (tagname != null && tagname.equals(tag12)){
                            tag12VALUE = parser.getAttributeValue(0);
                            InputStream input = new URL(tag12VALUE).openStream();
                            myBitmap = BitmapFactory.decodeStream(input);
                            IV.setImageBitmap(myBitmap);
                        }
                         break;

                    case XmlPullParser.START_TAG:
                        tagname = parser.getName();
                        break;

                    case XmlPullParser.END_TAG:
                        tagname = parser.getName();
                        break;
                }
            }

        } catch (Throwable t) {
            Toast.makeText(this,
                    "Error while loading xml document: " + t.toString(), Toast.LENGTH_LONG)
                    .show();
        }

        SomeItemAdapter adapter = new SomeItemAdapter(this, R.layout.list_item, items);
        listView.setAdapter(adapter);
    }

这是我的适配器：

public class SomeItemAdapter extends ArrayAdapter<SomeItem>{
    private LayoutInflater inflater;
    private int layout;
    private List<SomeItem> items;

    public SomeItemAdapter (Context context, int resource, List<SomeItem> items) {
        super(context, resource, items);
        this.items= items;
        this.layout = resource;
        this.inflater = LayoutInflater.from(context);
    }
    public View getView(int position, View convertView, ViewGroup parent) {

        View view=inflater.inflate(this.layout, parent, false);

        ImageView icon = view.findViewById(R.id.iconsrc);
        TextView nameView = view.findViewById(R.id.name);

            SomeItem item = items.get(position);

            //i think here i must TODO some code with ImageView and TextView, 
smth like setImageResource and setText, but how I can do this If I getting my text and image while parsing?

            return view;
        }
    }

最后一堂课，有我的作品：

public class SomeItem{

    private String name;
    private ImageView iconsrc;

    public SomeItem(String name, ImageView iconsrc){

        this.name=name;
        this.iconsrc=iconsrc;
    }

    public String getName() {
        return this.name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public ImageView getIconResource() {
        return this.iconsrc;
    }

    public void setIconResource(ImageView iconsrc) {
        this.iconsrc = iconsrc;
    }

}

list_item.xml：

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:orientation="horizontal"
    android:padding="16dp">
    <ImageView
        android:id="@+id/iconsrc"
        android:layout_marginRight="16dp"
        android:layout_marginEnd="16dp"
        android:layout_width="40dp"
        android:layout_height="40dp" />

    <LinearLayout
        android:orientation="vertical"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_marginTop="10dp"

        >

        <TextView
            android:id="@+id/name"
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:text="Name"
            android:gravity="center|left"
            />

    </LinearLayout>
</LinearLayout>

我希望获取带图像的ListView，该URL是从xml解析的，并且将从此xml中的标记中获取一些文本。但是实际上我的ListView中什么也没得到。

正如我在代码中所写的那样，我认为我不是我的适配器的财产，所以主要问题是：我的代码有什么问题以及如何获取具有解析数据的ListView？

UPD： 列表视图中的文本问题已解决，但现在图像加载出现问题：

if (tagname != null && tagname.equals(tag12)){

这里的tagname = tag11，为什么？我应该在其他地方或其他地方调用parser.next（）？

解析xml时一无所获

0 个答案: