Question

我想获得可以接受字符串参数并将其返回为json格式的函数。例如，如果我调用$ ballcolor-> getBall（“ orange”）; 那么输出//应该是： {“ color”：“ orange”，“ ball”：[“ basketball”]}

并且如果呼叫没有该球的任何颜色： {“ color”：“ black”，“ ball”：[]}

class BallColor
    {
      private $ballcolor;

      function BallColor($ballcolor)
      {
        $this->ballcolor = $ballcolor;
      }

      public function getBall($color)
      {

        return NULL;

      }
    }

    $ballcolor = new BallColor(array(
        "orange" => array("basketball"),
        "white" => array("football")
    ));

    echo $ballcolor->getBall("orange");
    echo "\n";
    echo $ballcolor->getBall("black");

Answer 1

您应该使用

function __construct($ballcolor)

代替

function BallColor($ballcolor)

作为构造函数，除非您的php版本太旧。

Answer 2

从$this->ballcolor中获取所需的值后，再构建您需要返回的数组，然后进行json_encode：

class BallColor
{
      private $ballcolor;

      function __construct($ballcolor)
      {
        $this->ballcolor = $ballcolor;
      }

      public function getBall($color)
      {
          // condensed into oneliners:
          if(isset($this->ballcolor[$color])) {
              return json_encode(Array("color" => $color, "ball" => $this->ballcolor[$color]));
          } else {
              return json_encode(Array("color" => "black", "ball" => []));
          }
      }
}

$ballcolor = new BallColor(array(
    "orange" => array("basketball"),
    "white" => array("football")
));

echo $ballcolor->getBall("orange");
echo "\n";
echo $ballcolor->getBall("black");

输出：

{"color":"orange","ball":["basketball"]} 
{"color":"black","ball":[]}

我需要实现将颜色作为字符串参数并将其作为json_encode返回的函数

2 个答案: