查找777文件和文件夹的脚本,如何进行改进并使其与python 2.4(RHEL5)兼容

时间:2019-04-04 11:14:47

标签: python rhel5

我有以下代码,这是我的第一个python脚本。它应该查找具有777权限的文件和文件夹,同时排除某些文件夹,例如/ proc等

有什么办法可以改善脚本?

DetailsActivity

我还需要对其进行修改,因为我们有几个旧的rhel5服务器,并且代码无法使用奇怪的语法错误进行工作:

#!/usr/bin/env python


import os, sys, socket,csv

from os.path import join

mode = int('777', 8) 
results = {} 
host = socket.gethostname() 
results[host] = {}

exclude = ['proc', 'run']

def get_username(uid):
    import pwd
    try:
        return pwd.getpwuid(uid).pw_name
    except KeyError:
        return uid


def find_files():
    for (dirpath, dirnames, filenames) in os.walk('/'):
        dirnames[:] = [d for d in dirnames if d not in exclude]
        listoffiles = [join(dirpath, file) for file in filenames]
        listoffiles += [join(dirpath,dir) for dir in dirnames]
        for path in listoffiles:
            try:
                statinfo = os.stat(path)
            except OSError:
               #print(path)
               pass
            if (statinfo.st_mode & 0o777) == mode:
                results[host][path] = {}
                results[host][path]['owner'] = get_username(statinfo.st_uid)
                results[host][path]['perm']  = oct(statinfo.st_mode & 0o777)
    return results

find_files()

resultstxt = csv.writer(open('results_%s.csv' % host, 'w')) for hostname,data in results.items():
    for path, attributes in data.items():
      resultstxt.writerow([hostname, path, attributes['perm'], str(attributes['owner'])])

1 个答案:

答案 0 :(得分:0)

使用0777代替0o777

Python 2.4中不提供八进制数字的0o前缀。传统的0前缀在Python 3之前有效。