Question

如何使在画布上绘制的图像对所有屏幕尺寸均有效？我的代码无法正常工作，涂漆的游戏屏幕对于小屏幕来说太大了，对大屏幕来说太小了，我已经尝试了所有方法，但仍然没有任何效果，我希望画布根据屏幕的大小进行缩放

这是我得到的结果，也是所需的结果：https://imgur.com/a/bSnGfov

这是我的游戏画布代码：

public class CanvasView extends View {
    Me me;
    public int width;
    public int height;
    public int fx,fy,zx,zy;
    int[][]lines;
    private Bitmap pme, wall,finish,redlock,redkey,bluelock,bluekey,greenlock,greenkey ,mBitmap,white,c1,c2,c3,c4,c5,c6,c7
            ,c8,c9,c10,c11,c12;
    private Canvas mCanvas;
    private Path mPath;
    Context context;
    private Paint p;
    private int mx, my,character;private int dir;
    private static final float TOLERANCE = 5;float bb;string bbb; int sz;int fz;
    public CanvasView(Context c,int[][] l,Me m,int mxx,int myy,int chara) {
        super(c);
        lines=l;
        mx = mxx;
        my = myy;
        context = c;
        fx=6;fy=6;zx=0;zy=0;
        me = m;
        character=chara;
        mPath = new Path();

        p = new Paint();
        p.setAntiAlias(true);
        p.setColor(Color.BLACK);
        p.setStyle(Paint.Style.STROKE);
        p.setStrokeJoin(Paint.Join.ROUND);
        p.setStrokeWidth(4f);
    }

    // override onSizeChanged
    @Override
    protected void onSizeChanged(int w, int h, int oldw, int oldh) {
        super.onSizeChanged(w, h, oldw, oldh);

        // your Canvas will draw onto the defined Bitmap
        mBitmap = Bitmap.createBitmap(w, h, Bitmap.Config.ARGB_8888);
        mCanvas = new Canvas(mBitmap);
    }

    // override onDraw
    @Override
    protected void onDraw(Canvas canvas) {
        super.onDraw(canvas);

        int width = mx;
        int height = my;float calc = getResources().getDisplayMetrics().density;
        canvas.drawBitmap(pme,calc*( (me.GetCenterX() - 24)+zx),calc*( (me.GetCenterY() - 24)+zy), p);
        int px = (me.GetCenterX() - 24) / 48;
        int py = (me.GetCenterY() - 24) / 48;
        for (int j = 0; j < fx; j++)
        {
            for (int i = 0; i < fy; i++)
                if (i < height)
                {

                    float tileX = ((j * 48) + zx) * calc;
                    float tileY = ((i * 48) + zy) * calc;
                    int type = lines[i][j];
                    switch (type)
                    {
                        case 1:
                            canvas.drawBitmap(wall, tileX,tileY, p);
                            break;
                        case 3:
                            canvas.drawBitmap(finish, tileX,tileY, p);
                            break;
                        case 4:
                            canvas.drawBitmap(bluelock, tileX,tileY, p);
                            break;
                        case 5:
                            canvas.drawBitmap(bluekey, tileX,tileY, p);
                            break;
                        case 6:
                            canvas.drawBitmap(redlock, tileX,tileY, p);
                            break;
                        case 7:
                            canvas.drawBitmap(redkey, tileX,tileY, p);
                            break;
                        case 8:
                            canvas.drawBitmap(greenlock, tileX,tileY, p);
                            break;
                        case 9:
                            canvas.drawBitmap(greenkey, tileX,tileY, p);
                            break;
                    }
                }

            }
        }

        for (int i = 0; i <= 6;i++ )
        {
            canvas.drawBitmap(white, 6*48* calc,i*48* calc, p);
        }
        for (int j = 0; j <= 5; j++)
        {
            canvas.drawBitmap(white, j*48* calc,6*48* calc, p);
        }

    }


}

Answer 1

您可以动态请求Android设备屏幕的尺寸。

 Display display = getWindowManager().getDefaultDisplay();
 Point size = new Point();
 display.getSize(size);
 int width = size.x;
 int height = size.y;

获取当前显示的句柄-请注意，如果从应用程序上下文调用，则将获得物理屏幕的大小。如果从活动中调用，您将获得应用程序窗口的当前大小。

如何使涂漆的画布适合所有屏幕尺寸？

1 个答案: