Question

我有一个输入类型密码可以输入密码，还有一个显示密码复选框，可以将输入类型密码更改为文本，因此输入密码字符是可见的。还有一个“随机密码”按钮，用于使密码随机化，并在单击按钮时选中复选框以显示密码。

问题是，当单击随机密码按钮以触发JavaScript代码检查显示密码复选框时，onchange复选框功能未触发/运行。这是我的代码

    function togglePassword(checkbox) {
        var x = document.getElementById("staff-password");
        if (checkbox.checked == true){
          x.type = "text";
        } else {
          x.type = "password";
        }
    }
    
    function clickRandom(){ 
      var randomPass = randomPass();
      document.getElementById("staff-password").value(randomPass);
      document.getElementById("show-password").checked = true;
    }
    
    function randomPass() {
      var length = 6;
      var text = "";
      var possible = "3907154628";
      for (var i = 0; i < length; i++){
        text += possible.charAt(Math.floor(Math.random() * possible.length));
      }
      return text;
    }

    <span> Password </span>
    <input type="password" name="password" id="staff-password" maxlength="6" value="">
    <br/>
    <input type="checkbox" onchange="togglePassword(this)" id="show-password" >
    <span style="margin-left:3px;">Show Password</span>
    <br/>
    <button type="button" id="random-password" onclick="clickRandom()">
      <span>Random password</span>
    </button>

Answer 1

正确的是，对表单字段状态的动态更新不会导致用户交互中引发的典型事件。相反，您可以自己手动调用回调。

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function togglePassword(checkbox) {
        var x = document.getElementById("staff-password");
        if (checkbox.checked == true){
          x.type = "text";
        } else {
          x.type = "password";
        }
    }
    
    function clickRandom(){ 
      // value is a property, you have to assign it a value:
      document.getElementById("staff-password").value = randomPass();
      document.getElementById("show-password").checked = true;
      togglePassword(document.getElementById("show-password")); // Manually call the toggle function
    }
    
    function randomPass() {
      var length = 6;
      var text = "";
      var possible = "3907154628";
      for (var i = 0; i < length; i++){
        text += possible.charAt(Math.floor(Math.random() * possible.length));
      }
      return text;
    }

<span> Password </span>
    <input type="password" name="password" id="staff-password" maxlength="6" value="">
    <br/>
    <input type="checkbox" onchange="togglePassword(this)" id="show-password" >
    <span style="margin-left:3px;">Show Password</span>
    <br/>
    <button type="button" id="random-password" onclick="clickRandom()">
      <span>Random password</span>
    </button>

从JavaScript代码强制选中复选框时，复选框onchange函数不会触发

1 个答案: