Question

我有list的{{1}}：

lists

我想遍历my_list_of_lists = [['a', 'keep me alone'], ['b', 'keep me alone'], ['c', 'Put me with previous value'], ['d', 'keep me alone']]并在my_list_of_lists时合并一个值。

所需的输出是这样：

my_list[1] == 'Put me with previous value'

我尝试了以下代码，但始终遇到my_updated_list_of_lists = [['a', 'keep me alone'], ['bc', 'keep me alone'], ['d', 'keep me alone']]错误：

IndexError: list index out of range

由于n = 0 my_updated_list_of_lists = [] for my_list in my_list_of_lists: n = n+1 if my_list[1] == 'Put me with previous value': my_updated_list_of_lists[n-1][0] = my_updated_list_of_lists[n-1][0] + my_list[0] continue else: my_updated_list_of_lists.append(my_list)列表项的性质（这是一个后缀，这是我正在利用的语音功能的一部分），我认为它不会成为列表中的第一项。

如果发生问题，我本希望代码会中断，但是我什至无法运行它。

谢谢您的帮助！

Answer 1

这应该做到。

my_list_of_lists = [['a', 'keep me alone'],
                    ['b', 'keep me alone'],
                    ['c', 'Put me with previous value'],
                    ['d', 'keep me alone']]

my_updated_list_of_lists = []

for i in range(0, len(my_list_of_lists)):

    elem = my_list_of_lists[i]

    #Merge the first element of 2 consecutive items if second item contains Put me with previous value
    if i+1 < len(my_list_of_lists) and my_list_of_lists[i+1][1] == 'Put me with previous value':
        elem[0] = elem[0]+my_list_of_lists[i+1][0]
    #Ignore element containing Put me with previous value
    elif elem[1] == 'Put me with previous value':
        continue
    #Append element to new list
    my_updated_list_of_lists.append(elem)

print(my_updated_list_of_lists)
#[['a', 'keep me alone'], ['bc', 'keep me alone'], ['d', 'keep me alone']]

如何有条件地更新以前的迭代器附加值？

1 个答案: