隐式构造函数中的多个const

Question

我有一个带有多个const声明的结构。我知道，当您的结构体中有一个const时，您可以在构造函数中隐式声明其值。但是，当我尝试对多个const执行此操作时，它将无法编译。在构造函数中声明多个const的正确方法是什么？

    struct RLdata
    {
      const double alpha;
      const double gamma;
      const double beta;
      int count = 0;
      bool action; //0  = BUY, 1 = SELL
      double Qbuy = 1;
      double Qsell = 0;
      std::vector reward;
      //This below works if I just have one of the variables implicitly, but not with 3. 
      RLdata(const double &a, const double &g, const double &b) : alpha(a), gamma(g), beta(b){} 
    };

    ./RL.h:29:8: note: candidate constructor (the implicit copy constructor) not
          viable: requires 1 argument, but 3 were provided
    struct RLdata
           ^
    ./RL.h:29:8: note: candidate constructor (the implicit move constructor) not
          viable: requires 1 argument, but 3 were provided
    1 error generated.