Question

我在Codeigniter中拥有2个模型，其中1个获得所有房间，第二个模型正在选择日期范围内的已预订房间。

在我看来，我可以列出所有带有foreach的房间，当我为预订的房间插入另一个foreach以红色显示时，我得到了结果，但是看到重复的结果

我的模特：

public function rooms(){
    $result = $this->db->select('*')
    ->from('rooms')
    ->group_by('room_id')
    ->get()
    ->result();

    return $result;
}


public function check_room_availability($start, $end){
    $this->db->select('*');
    $this->db->from('room_actions as ra', 'rooms as r');
    $this->db->join('rooms as r', 'r.room_id = re.room_id', 'LEFT'); 
    $this->db->where('ra.days >=', $start);
    $this->db->where('ra.days <=', $end); 
    $this->db->group_by('ra.room_id'); 

    $query = $this->db->get()->result();

    return $query;
    }

我的观点：

<?php foreach($all_rooms as $room) { 
    foreach($booked_ones as $booked) {?>
  <div class="<?php
      if($booked->room_id == $room->room_id){
        echo 'room_box red';}
        else{
          echo 'room_box green';}?>">

      <?php echo $room->room_id; ?>
  </div>
<?php } ?>
 <?php } ?>

如果您能帮助我，我将不胜感激。谢谢。

如下图所示，如果我在所选日期预订了2个房间，则我的房间重复。如果我预订了3个房间，那么它将变成X 3。

https://pasteboard.co/I8AkG8i.jpg

Answer 1

尝试一下

public function check_room_availability($start, $end) {
        $this->db->select('r.room_id as room_id,ra.room_id as booked_room_id');
        $this->db->from('rooms as r');
        $this->db->join('room_actions as ra', 'r.room_id = ra.room_id', 'LEFT');
        $this->db->where('ra.days >=', $start);
        $this->db->where('ra.days <=', $end);
        $query = $this->db->get();
        if ($query->num_rows() > 0) {
            return $query->result();
        } else {
            return array();
        }
    }

OR

public function check_room_availability($start, $end) {
        $this->db->select('*,(select room_id from room_actions as ra where ra.room_id = r.room_id and ra.days >=' . $start . ' and ra.days <=' . $end . ') as booked_room_id');
        $this->db->from('rooms as r');
        $query = $this->db->get();
        if ($query->num_rows() > 0) {
            return $query->result();
        } else {
            return array();
        }
}

为了获得更好的结果，请共享您的表或预期的输出，据此我可以更新查询

Answer 2

尝试一下，希望对您有所帮助。

如果rooms表具有唯一的room_id，则无需使用group_by()

public function rooms(){
$result = $this->db->select('*')
->from('rooms')
->get()
->result();

return $result;
}

这里不需要join()

public function check_room_availability($start, $end){

$booked_rooms = array(); 

$this->db->select('room_id');
$this->db->from('room_actions as ra');
$this->db->where('ra.days >=', $start);
$this->db->where('ra.days <=', $end); 
$query = $this->db->get()->result();
if(isset($query) && count($query) > 0){
   foreach($query as $row){
    if(!in_array($row->room_id, $booked_rooms)){
       array_push($booked_rooms, $row->room_id);
    }
   }
} 
return $booked_rooms;
}

现在，您有一个简单的预订房间ID数组。在视图中，只需执行一个forach()循环

foreach($all_rooms as $room) {
   if(in_array($room->id, $booked_rooms)){
       //Room is booked
   }
}

Codeigniter，在嵌套Foreach之后复制结果

2 个答案: