如何替换XSLT中的选择字符

时间:2019-04-03 20:27:15

标签: xml xslt

我正在处理类似

的XML文件
<?xml version="1.0" encoding="UTF-8"?>
<Properties>
    <Property>
        <Name>Email</Name>
        <Value>alebbb@hotmail.com</Value>
    </Property>
    <Property>
        <Name>Resposta</Name>
        <Value>here "i" have ; to be"" replace by nothing</Value>
    </Property>
    <Property>
        <Name>NPS</Name>
        <Value>8</Value>
    </Property>
</Properties>

我的地图XSLT就像:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/">
  <xsl:output method="text" omit-xml-declaration="yes" indent="no"/>
  <xsl:strip-space elements="*"/>
    <xsl:template match="Properties">
       <xsl:variable name="Email" select="/Properties/Property[1]/Value/text()"/>
       <xsl:variable name="Resposta" select="/Properties/Property[2]/Value/text()"/>
       <xsl:variable name="NPS" select="/Properties/Property[3]/Value/text()"/>
       <xsl:value-of select="normalize-space($Email)"/>;<xsl:value-of select="normalize-space($Resposta)"/>;<xsl:value-of select="normalize-space($NPS)"/>
    </xsl:template>
</xsl:stylesheet>

如何在我的XSLT映射上使用replace完全替换;"""
我得到了:

here "i" have ; to be"" replace by nothing

预期:

here i have  to be replaced by nothing

我正在使用以下内容代替;

<xsl:value-of select="normalize-space(translate($Resposta,';',' '))"/>

1 个答案:

答案 0 :(得分:2)

给出:

<Value>here "i" have ; to be"" replace by nothing</Value>

说明:

<xsl:value-of select="normalize-space(translate(Value, ';&quot;', ''))"/>

将返回:

here i have to be replace by nothing

演示https://xsltfiddle.liberty-development.net/ncdD7mt