我有一个包含两列的表import { trigger, animate, transition, style, state } from '@angular/animations';
export const buttonFadeIn =
trigger('buttonFadeIn', [
state('in', style({
opacity: 1,
})),
transition("* => in", animate('500ms ease-in-out')),
state('out', style({
opacity: 0,
})),
transition("* => out", animate('220ms ease'))
]);
:
我需要将guest
列的所有记录更新为IMG
列中提到的位置中存在的二进制数据。
IMAGE
此SQL语句一次将仅更新一个记录。但是我需要将每个记录的与jpeg文件对应的所有记录更新为UPDATE guest
SET img = (SELECT bulkcolumn
FROM OPENROWSET(BULK N'D:\Webcam Images\24092018071230.jpg', SINGLE_BLOB) AS X)
WHERE ID = 53
数据类型列Image
。
答案 0 :(得分:0)
我无法直接测试此代码,但是类似的事情应该起作用(您也可以将其重写为游标,添加错误检查等):
create table #guest (
ID int,
FilePath varchar(50),
FileImage image,
Updated tinyint
)
insert into #guest (ID, FilePath, FileImage, Updated)
select ID, Image, IMG, 0
from guest
declare @sql varchar(1500), @FilePath varchar(50), @ID int
while exists (select top 1 ID from #guest where Updated = 0)
begin
select top 1 @ID = ID, @FilePath = FilePath from #guest where Updated = 0
select @sql = 'update #guest set FileImage = ' + '(select bulkcolumn from openrowset(bulk n''' + @FilePath + ', SINGLE_BLOB) AS X) where ID = ' + @ID
exec sp_executesql @sql
update #guest set Updated = 1 where ID = @ID
end
update g
set g.IMG = #guest.FileImage
from guest g
inner join #guest on g.ID = #guest.ID