我正在尝试使用Javascript为BigQuery编写用户定义的函数,该函数返回一个结构并生成两列:
CREATE TEMP FUNCTION exampleFunction(exampleString STRING)
RETURNS STRUCT<index INT64, latency INT64> LANGUAGE js AS
LANGUAGE js AS
"""
var exampleStruct = {1:100, 2:200}
return exampleStruct;
""";
我的查询将是这样的:
SELECT
exampleCol,
exampleFunction(stringCol) -- use SELECT AS STRUCT somewhere here? with the aliases “First” and “Second”
FROM
[SOME DATATBASE HERE]
我希望exampleFunction(stringCol)
的输出生成两列(如果包含exampleCol
,则总共为三列)。例如,如果exampleCol
为我们提供了“ SOMETHING”,我想返回以下列:“ SOMETHING”(例如“ Col”),1(“ First”)和“ Second”(第二)。这有可能吗?
我无法从JS函数返回STRUCT(不确定我的语法是否关闭),并且无法正确查询。对于查询,我想避免两次运行JavaScript函数。谢谢!
答案 0 :(得分:1)
以下示例适用于BigQuery标准SQL
#standardSQL
CREATE TEMP FUNCTION exampleFunction(exampleString STRING)
RETURNS STRUCT<index INT64, latency INT64>
LANGUAGE js AS
"""
arr = exampleString.split(':');
this.index = arr[0];
this.latency = arr[1];
return this;
""";
WITH `project.dataset.table` AS (
SELECT 1 exampleCol, '10:100' stringCol UNION ALL
SELECT 2, '20:200' UNION ALL
SELECT 3, '30:456'
)
SELECT exampleCol, exampleFunction(stringCol).*
FROM `project.dataset.table`
-- ORDER BY exampleCol
有结果
Row exampleCol index latency
1 1 10 100
2 2 20 200
3 3 30 456
注意:如果您想为列分别命名为First,Second,则可以分别用index
和latency
替换first
和second
,如下面的示例< / p>
#standardSQL
CREATE TEMP FUNCTION exampleFunction(exampleString STRING)
RETURNS STRUCT<first INT64, second INT64>
LANGUAGE js AS
"""
arr = exampleString.split(':');
this.first = arr[0];
this.second = arr[1];
return this;
""";
SELECT exampleCol, exampleFunction(stringCol).*
FROM `project.dataset.table`
或者您可以使用以下方法
#standardSQL
CREATE TEMP FUNCTION exampleFunction(exampleString STRING)
RETURNS STRUCT<index INT64, latency INT64>
LANGUAGE js AS
"""
arr = exampleString.split(':');
this.index = arr[0];
this.latency = arr[1];
return this;
""";
SELECT exampleCol, index AS first, latency AS second
FROM (
SELECT exampleCol, exampleFunction(stringCol).*
FROM `project.dataset.table`
)
在两种情况下均具有以下结果
Row exampleCol first second
1 1 10 100
2 2 20 200
3 3 30 456
答案 1 :(得分:0)
我想补充米哈伊尔·伯利安(Mikhail Berlyant)的答案,在这种情况下效果很好,但是在稍微不同的情况下我遇到了问题。
我建议不要使用JavaScript中的“ this”来保留行中的数据,而建议使用新的对象来实现。
在我的示例中,我想再返回一个列,该列值基于另一个现有列的值。我将再添加一列名为“ latencyUnder150”的列,如果延迟字段的值小于150,则其值为“ Y”,否则请将该字段留空。
#standardSQL
CREATE TEMP FUNCTION exampleFunction(exampleString STRING)
RETURNS STRUCT<index INT64, latency INT64, latencyUnder150 STRING>
LANGUAGE js AS
"""
arr = exampleString.split(':');
this.index = arr[0];
this.latency = arr[1];
if (this.latency < 150) {
this.latencyUnder150 = 'Y'
}
return this;
""";
WITH `project.dataset.table` AS (
SELECT 1 exampleCol, '10:100' stringCol UNION ALL
SELECT 2, '20:200' UNION ALL
SELECT 3, '30:456'
)
SELECT exampleCol, exampleFunction(stringCol).*
FROM `project.dataset.table`
-- ORDER BY exampleCol
在JS中使用“ this”变量,您将获得此答案。
| Row | exampleCol | index | latency | latencyUnder150 |
|-----|------------|-------|---------|-----------------|
| 1 | 1 | 10 | 100 | Y |
| 2 | 2 | 20 | 200 | Y |
| 3 | 3 | 30 | 456 | Y |
从第一条记录中您可以看到,latencyUnder150字段保留值为“ Y”。
通过稍微更改代码以使用新对象,每一行从上一行开始就没有值。
#standardSQL
CREATE TEMP FUNCTION exampleFunction(exampleString STRING)
RETURNS STRUCT<index INT64, latency INT64, latencyUnder150 STRING>
LANGUAGE js AS
"""
var outObj = {}
arr = exampleString.split(':');
outObj.index = arr[0];
outObj.latency = arr[1];
if (outObj.latency < 150) {
outObj.latencyUnder150 = 'Y'
}
return outObj;
""";
WITH `project.dataset.table` AS (
SELECT 1 exampleCol, '10:100' stringCol UNION ALL
SELECT 2, '20:200' UNION ALL
SELECT 3, '30:456'
)
SELECT exampleCol, exampleFunction(stringCol).*
FROM `project.dataset.table`
-- ORDER BY exampleCol
| Row | exampleCol | index | latency | latencyUnder150 |
|-----|------------|-------|---------|-----------------|
| 1 | 1 | 10 | 100 | Y |
| 2 | 2 | 20 | 200 | (null) |
| 3 | 3 | 30 | 456 | (null) |