Question

我有一个查询，该查询将SQL Server 2008 R2 Express中的7个表与总共852列连接在一起。我试图用该查询的输出创建一个新表

尝试使用INTO，但由于表中的某些列具有重复名称，因此无法正常使用

USE VistaBI
SELECT *
INTO NewTable
FROM         dbo.Agente FULL JOIN
                      dbo.Cte ON dbo.Agente.Agente = dbo.Cte.Agente 
                      FULL JOIN
                      dbo.CteEnviarA ON dbo.Agente.Agente = dbo.CteEnviarA.Agente 
                      FULL JOIN
                      dbo.Unidad ON dbo.CteEnviarA.Unidad = dbo.Unidad.Unidad 
                      FULL JOIN
                      dbo.Venta ON dbo.Agente.Agente = dbo.Venta.Agente 
                      FULL JOIN
                      dbo.VentaD ON dbo.Agente.Agente = dbo.VentaD.Agente 
                      FULL JOIN
                      dbo.Art ON dbo.VentaD.Articulo = dbo.Art.Articulo
                      FULL JOIN 
                      dbo.Alm ON dbo.Venta.Almacen = dbo.Alm.Almacen

有没有一种方法可以自动创建表，而不必用唯一的名称和数据类型键入852列中的每一个？

Answer 1

我是动态完成的，请尝试以下代码：列名将变为表名+列名，因此不会重复任何列名。

User_ID Game_ID Like/Share  Category    Game_repeat Rating
      1      11          1         1              2      4
      1      22          2         1              0      3
      1      33          0         0              0      0
      2      33          1         0              0      1
      2      44          2         0              0      2
      2      11          0         0              0      0

Answer 2

显式选择列名，而不使用*

在下面，我使用两个表

select 
    a.person_id,
    a.city,
    city.city_id
into 
    mytable 
from 
    table1 a
inner join 
    city on a.city = city.city

所以就您而言

SELECT table_name.col1,table_nae.col2..... use explicitly column name in selection
INTO NewTable
FROM         dbo.Agente FULL JOIN
                      dbo.Cte ON dbo.Agente.Agente = dbo.Cte.Agente 
                      FULL JOIN
                      dbo.CteEnviarA ON dbo.Agente.Agente = dbo.CteEnviarA.Agente 
                      FULL JOIN
                      dbo.Unidad ON dbo.CteEnviarA.Unidad = dbo.Unidad.Unidad 
                      FULL JOIN
                      dbo.Venta ON dbo.Agente.Agente = dbo.Venta.Agente 
                      FULL JOIN
                      dbo.VentaD ON dbo.Agente.Agente = dbo.VentaD.Agente 
                      FULL JOIN
                      dbo.Art ON dbo.VentaD.Articulo = dbo.Art.Articulo
                      FULL JOIN 
                      dbo.Alm ON dbo.Venta.Almacen = dbo.Alm.Almacen

Answer 3

您可以做的是首先创建一个表，然后使用动态alter语句添加所需的列数：

public void nextSong() {
    index += 1;
    mediaPlayer.stop();

    if (index > songs.listOfFiles.size() - 1) {
        index = 0;
    }
    hit = new Media(songs.listOfFiles.get(index).toURI().toString());
    mediaPlayer = new MediaPlayer(hit);
    mediaPlayer.play();
    changeTitle();
}




if(mediaPlayer.getStatus() == MediaPlayer.Status.STOPPED){
        nextSong();
}

然后只需将插入语句更改为：

CREATE TABLE MYTABLE 
(
A INT,
B INT
)


DECLARE @I INT = 1, @COLNAME VARCHAR(20),@SQL VARCHAR(MAX)
WHILE (@I < 852)
BEGIN
SET @COLNAME = CAST(@I AS VARCHAR(20))


SET @SQL ='
ALTER TABLE MYTABLE
ADD [' + @COLNAME + '] VARCHAR(MAX);'
PRINT @SQL
EXEC(@SQL)
SET @I = @I + 1

END

这将为您提供列名称为1,2,3 ....等的结果，但这是一个动态名称，使您不必手动命名列。

从Select查询创建表

3 个答案: