Question

我可以调用我想在网站上显示的所有信息，但实际上我只需要显示某些数据，例如仅项目ID为1的事物。

我尝试了一些while函数。

//creating connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} 
$sql = "SELECT id, user_id, project_id, hours FROM hours_worked";
$result = $conn->query($sql);

Answer 1

只需将您的sql查询更改为：

$sql = "SELECT  id, user_id, project_id, hours FROM hours_worked WHERE project_id ='".$project_id."';

根据需要更改WHERE子句。如果只想显示与特定用户关联的记录，则将WHERE子句更改为：

WHERE user_id = *ENTER USER ID HERE*

从数据库获取特定信息以显示在网站上

1 个答案: