Question

我在下面的查询中没有获得如何使用％？％的信息。这给了我错误：

PreparedStatementCallback; SQL的未分类SQLException [选择 *来自名称如'％？％']
的名称

问题：

String sql = "select * from names where name like ?";
List<NamesModel> names = jdbcTemplate.query(sql, new Object[]{searchName}, new NamesRowMapper());

Answer 1

您的异常告诉您不能绑定到引用的值。下面将不起作用：

SELECT c.id,
       c.coursename,
       t.teachername,
       s.studentname
FROM  (SELECT id,
              teachername,
              row_number()
                OVER(
                  partition BY id
                  ORDER BY id) AS teach
       FROM   table2)AS t
      FULL JOIN(SELECT id,
                       studentname,
                       row_number()
                         OVER(
                           partition BY id
                           ORDER BY id) AS stud
                FROM   table3) AS s
             ON( t.teach = s.stud
                 AND t.id = s.id )
      RIGHT JOIN (SELECT id,
                         coursename
                  FROM   table1) AS c
              ON( c.id = s.id
                   OR c.id = t.id )

正确的方法是在<link rel="stylesheet" type="text/css" href="./calc.css"> <script src="./calc.js"></script>参数值周围添加String sql = "select * from names where name like '%?%'"; List<NamesModel> names = jdbcTemplate.query(sql, new Object[]{ searchName }, new NamesRowMapper());：

JDBC模板使用“ like”为查询提供错误

1 个答案: