Question

我的结果集如下：

client_id   status
------------------
67          1
67          0
67          0
67          0
77          0

我只需要获取client_id条目为latest (top)的{{1}}。

我尝试关注，但都获得了0。 67 and 77应该排除在外。

如何设置条件，以便我只能获取SELECT DISTINCT client_id FROM ( SELECT client_id, status FROM client_history WHERE (DATE(updated_on) BETWEEN '$from' AND '$to') ORDER BY DATE(updated_on) DESC ) as ch WHERE status = 0 GROUP BY client_id为0的那些记录？

Answer 1

使用不存在的相关子查询

select distinct client_id
from lient_history a
where not exists (select 1 from lient_history b where a.client_id=b.client_id 
  and status=1) 
and (DATE(updated_on) BETWEEN '$from' AND '$to')

Answer 2

要获取最新条目，可以使用相关子查询：

select ch.*
from client_history ch
where ch.updated_on = (select max(ch2.updated_on)
                       from client_history ch2
                       where ch2.client_id = ch.client_id and
                             date(updated_on) between ? and ?
                      );

请注意，它使用参数占位符（?）而不是字符串替换来传递值。

为此，您只需添加：

and status = 0

进行所需的过滤。

Answer 3

请尝试以下一项，我认为它将解决您的问题。

Declare @FromDate Date, @ToDate Date
Set @FromDate = -- whatever date range you wanted to give
Set @ToDate =  -- whatever date range you wanted to give
SELECT DISTINCT client_id FROM dbo.Client_history 
WHERE cast(updated_on as DATE)>=@FromDate and cast(updated_on as DATE)<=@ToDate
AND status = 0
ORDER BY DATE(updated_on) DESC

为每个组值mysql获取不同的ID

3 个答案: