Question

我想遍历每个对象，并用system.myStringValue映射value.myStringValue

您可以提供相同的规格吗？

我提供了以下输入和输出json。如果有其他需要我支持的事情，请告诉我。我尝试使用另一种规格，但是它对我不起作用，因为我想将电子邮件和电话结合在一个对象中

输入：

[
  {
    "telecom": [
      {
        "system": {
          "myStringValue": "email"
        },
        "value": {
          "myStringValue": "mobqa@tester.com"
        }
      },
      {
        "system": {
          "myStringValue": "phone"
        },
        "value": {
          "myStringValue": "123"
        }
      }
    ]
  },
  {
    "telecom": [
      {
        "system": {
          "myStringValue": "email"
        },
        "value": {
          "myStringValue": "john.doe@tester.com"
        }
      }
    ]
  },
  {
    "telecom": [
      {
        "system": {
          "myStringValue": "email"
        },
        "value": {
          "myStringValue": "Gayle55@tester.com"
        }
      }
    ]
  }
]

输出：

{
  "users": [
    {
      "email":"mobqa@tester.com",
      "phone":"123"
    },
    {
      "email":"john.doe@tester.com"
    },
    {
      "email":"Gayle55@tester.com"
    }
  ]
}

Answer 1

[
  {
    "operation": "shift",
    "spec": {
      "*": {
        "telecom": {
          "*": {
            "value": {
              "myStringValue": {
                // @ takes value of 'value.myStringValue' and puts it into 'users[&5]' occurence
                // @(3,system.myStringValue) go up four levels and then go to 'system.myStringValue'
                // value and grab it and put as key value to appropriate occurence of 'users' 
                "@": "users[&5].@(3,system.myStringValue)" 
              }
            }
          }
        }
      }
    }
  }
]

比较和合并相同数组的对象

1 个答案: