Question

xls文件中的数字值无法正确读取，但字符串值很好

file, _ := xls.Open("test.xls", "utf-8")

    sheet := file.GetSheet(0)
    for r := 0; r <= (int(sheet.MaxRow)); r++ {
      row := sheet.Row(r)
      log.Println("column with numeric value: ", row.Col(0))
      log.Println("column with string value: ", row.Col(1))
    }

test.xls：

123 | test

456 | testing

输出：

column with numeric value: @

column with string value: test

column with numeric value: @

column with string value: testing

如何正确获取数值？

Answer 1

在Ubuntu 18.04上，我可以打开文件并打印第二列的内容

package main

import (
    "fmt"
    "github.com/extrame/xls"
    "log"
)


func main() {
if xlFile, err := xls.Open("test.xls", "utf-8"); err == nil {
    for i := 0; i < xlFile.NumSheets(); i++ {
        sheet := xlFile.GetSheet(i)
        fmt.Println(sheet.Name)
        for r := 0; r <= (int(sheet.MaxRow)); r++ {
                row := sheet.Row(r)
                log.Println("column ", row.Col(1))
        }
    }
}

}

要特别注意Col（1）索引。

输出

Sheet1
2019/04/03 14:28:29 column  test
2019/04/03 14:28:29 column  testi
2019/04/03 14:28:29 column  testing

但是对于数字列，我明白了

Sheet1
2019/04/03 14:27:46 column  General
2019/04/03 14:27:46 column  General
2019/04/03 14:27:46 column  General

我保存了与xlsx相同的文件。这适用于tealeg / xlsx包

import (
    "fmt"
    "github.com/tealeg/xlsx"
)

func main() {
    excelFileName := "test.xlsx"
    xlFile, err := xlsx.OpenFile(excelFileName)
    if err != nil {
        err = fmt.Errorf("can not open file!!!", err)
    return
    }
    for _, sheet := range xlFile.Sheets {
        for _, row := range sheet.Rows {
            for _, cell := range row.Cells {
                text := cell.String()
                fmt.Println(text)
            }
        }
    }
}

输出

123
test
788
456
testi
999
789
testing
100

从xls文件中读取值，但数值无法正确读取

1 个答案: