在GroupByKey之后减少PCollection

时间:2019-04-03 02:31:13

标签: python google-cloud-dataflow apache-beam

我正在尝试根据交易数据生成简单的客户摘要。例如,给定目标交易类型,发生了多少笔交易,总金额是多少?

原始输入示例:

accessibilityRole

所需输出示例:

custid  desc        amount
111     coffee      3.50
111     grocery     23.00
333     coffee      4.00
222     gas station 32.00
222     gas station 55.50
333     coffee      3.00

我的目标运行程序将是Dataflow(但当前使用DirectRunner进行测试)。

这是我所拥有的代码段:

custid nbr_coffee amt_coffee nbr_gas_station amt_gas_station
111    1          3.50       0               0.00
222    0          0          2               87.50
333    2          7.00       0               0

目前的实际结果是:

def categorize_coffee(transaction):

    if transaction['trx_desc'] == 'coffee':
        transaction['coffee'] = True
    else:
        transaction['coffee'] = False

    return transaction

def categorize_gas_station(transaction):

    if transaction['trx_desc'] == 'gas station':
        transaction['gas_station'] = True
    else:
        transaction['gas_station'] = False

    return transaction

def summarize_coffee(grouping):

    key, values = grouping
    values = list(values)

    nbr = 0
    amt = 0

    for d in values:
        if d['coffee'] == True:
            nbr+=1
            amt+=d['amount']

    ret_val = {}
    ret_val['cust'] = d['cust']
    ret_val['nbr_coffee'] = nbr
    ret_val['amt_coffee'] = amt

    return ret_val

def summarize_gas_station(grouping):

    key, values = grouping
    values = list(values)

    nbr = 0
    amt = 0

    for d in values:
        if d['gas_station'] == True:
            nbr += 1
            amt += d['amount']

    ret_val = {}
    ret_val['cust'] = d['cust']
    ret_val['nbr_gas_station'] = nbr
    ret_val['amt_gas_station'] = amt

    return ret_val

def create_dict(row):

    vars = row.split(',')
    return {'cust': vars[0], 'trx_desc': str(vars[1]), 'amount': float(vars[2])}

with beam.Pipeline(options=pipeline_options) as p:

    categorized_trx = (
        p | 'get data' >> beam.io.ReadFromText('./test.csv')
        | beam.Map(create_dict)
        | beam.Map(categorize_coffee)
        | beam.Map(categorize_gas_station)
        | beam.Map(lambda trx: (trx['cust'], trx))
        | beam.GroupByKey()
    )

    coffee_trx = (categorized_trx | beam.Map(summarize_coffee))

    gas_station_trx = (categorized_trx | beam.Map(summarize_gas_station))

    result = (coffee_trx, gas_station_trx) | beam.Flatten()

没有我所期望的扁平化或连接化。我是Beam的新手-不确定我是否了解如何正确解决此问题,所以会喜欢一些见识。

2 个答案:

答案 0 :(得分:0)

Beam提供Combine变换,该变换应允许您组合PCollection的元素。看起来在您的用例中,您可以使用Combine.perKey()来基于键组合PCollection的键元素。作为合并功能,您可以提供功能或实现CombineFn

答案 1 :(得分:0)

这应该有效:

...

def summarize_coffee(grouping):

    ...

    return (d['cust'], ret_val)


def summarize_gas_station(grouping):

    ...

    return (d['cust'], ret_val)

...

def processJoin(row):
    (customer, data) = row
    coffee_trx=data['coffee_trx']
    gas_station_trx=data['gas_station_trx']
    return (customer, coffee_trx, gas_station_trx)

result = ({coffee_trx: coffee_trx, gas_station_trx: gas_station_trx}
         | 'Group' >> beam.CoGroupByKey()    
         | 'Reshape' >> beam.Map(processJoin)
         | 'Unwind' >> beam.FlatMap(lambda x: x)
         )