This question提到了一种用于区分实例方法(传递self
)和静态方法(不传递任何东西)的技巧:
class X:
def id(self=None):
if self is None:
# It's being called as a static method
else:
# It's being called as an instance method
(贷记Tom Swirly)
但是,当继承开始起作用时,这很快就会成为一个问题,因为静态方法没有self
或cls
,因此无法在消息接收器上调用适当的方法。
我的问题是,我可以做这样的事情吗?
class X:
def get(self_or_cls):
if self_or_cls turns out to be cls:
return self_or_cls.class_method()
else:
return self_or_cls.instance_method()
class Y(X):
foo = str
@classmethod
def class_method(cls):
return cls.foo
def instance_method(self):
return self.foo()
>>> Y.get()
<class 'str'>
>>> Y().get()
''
感谢任何黑客!
答案 0 :(得分:1)
在this answer的帮助下,我为您找到了一种可能的破解方法:
class Custommethod:
def __get__(self, ins, cls):
if ins is None:
return lambda : cls.class_method()
else:
return lambda : ins.instance_method()
class X:
get = Custommethod()
class Y(X):
foo = str
@classmethod
def class_method(cls):
return cls.foo
def instance_method(self):
return self.foo()
print(Y.get()) # <class 'str'>
print(Y().get()) # ''