Question

我在大熊猫中进行绘图，遇到了熊猫链操作的以下问题

import numpy as np
import pandas as pd
import seaborn as sns

n = 365
df = pd.DataFrame(data = {"A":np.random.randn(n), "B":np.random.randn(n)+1},
                  index=pd.date_range(start="2017-01-01", periods=n, freq="D"))

df1 = df.stack().reset_index().set_axis(['month','vars','vals'],axis=1,inplace=False).set_index('month',drop=True)

sns.boxplot(x=df1.index.month, y="vals", hue="vars", data=df1)

如何使用单个熊猫链操作来做到这一点？

我的尝试：（给出错误的图像输出）

(df.stack().reset_index().set_axis(['month','vars','vals'],axis=1,inplace=False)
 .set_index('month',drop=False)
 .pipe( (sns.boxplot, 'data'), x='month', y="vals", hue="vars"))

所需图片：

问题

如何在ONE-LINER中获得上述外观的图像？

Answer 1

您想要使用lambda函数将数据帧传递给sns.boxplot吗？

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        $Conn = mysqli_connect(DB_HOST,DB_USER,DB_PASSWORD,DB_NAME);


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                }

            }

        endwhile; 

        ... RUN WEBSERVICE THAT GETS CLIENTS PRICES FOR THE 

        ... RUN THROUGH EACH PRODUCT RETURNED IN WEBSERVICE AND EXEC FOLLOWING UPDATE


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        FROM `wp_options`
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}
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如何链接涉及“索引”操纵的熊猫管道操作？

1 个答案: