我在javascript中有一个对象，该对象的键是我的段落的单词，该如何在段落中打印它.Value（key：value）保持其位置。
尝试使用for循环获取对我不起作用
var userdata= {
"\"Ten": [
0
],
"blue": [
1
],
"links\"": [
2
],
"have": [
3
],
"defined": [
4
],
"web": [
5,
36,
65
],
"search": [
6,
32,
37,
70,
90,
108,
126
],
"results": [
7,
33,
38,
71,
82,
99,
119
],
"for": [
8,
80
],
"the": [
9,
28,
56,
61,
69,
95,
105
],
"last": [
10
],
"fifteen": [
11
],
"years": [
12
],
"--": [
13
],
"snippets": [
14
],
"of": [
15,
30,
63,
97,
107,
125
],
"text": [
16
],
"combined": [
17
],
"with": [
18,
60
],
"document": [
19
],
"titles": [
20
],
"and": [
21,
46,
52,
85
],
"URLs.": [
22
],
"In": [
23
],
"this": [
24
],
"paper,": [
25
],
"we": [
26,
111,
114
],
"establish": [
27
],
"notion": [
29
],
"enhanced": [
31,
81,
98,
118
],
"that": [
34,
54,
75,
113
],
"extend": [
35
],
"to": [
39,
58,
103,
120
],
"include": [
40
],
"multimedia": [
41
],
"objects": [
42
],
"such": [
43
],
"as": [
44
],
"images": [
45
],
"video,": [
47
],
"intent-specific": [
48
],
"key": [
49
],
"value": [
50
],
"pairs,": [
51
],
"elements": [
53
],
"allow": [
55
],
"user": [
57
],
"interact": [
59
],
"contents": [
62
],
"a": [
64,
78,
122
],
"page": [
66
],
"directly": [
67
],
"from": [
68
],
"page.": [
72
],
"We": [
73,
92
],
"show": [
74,
112
],
"users": [
76,
102
],
"express": [
77
],
"preference": [
79
],
"both": [
83
],
"explicitly,": [
84
],
"when": [
86
],
"observed": [
87
],
"in": [
88,
100
],
"their": [
89
],
"behavior.": [
91
],
"also": [
93
],
"demonstrate": [
94
],
"effectiveness": [
96
],
"helping": [
101
],
"assess": [
104
],
"relevance": [
106
],
"results.": [
109
],
"Lastly,": [
110
],
"can": [
115
],
"efficiently": [
116
],
"generate": [
117
],
"cover": [
121
],
"significant": [
123
],
"fraction": [
124
],
"result": [
127
],
"pages.": [
128
]
};
“十个蓝色链接”定义了过去十五年的网络搜索结果-文本片段以及文档标题和URL。在本文中，我们建立了增强搜索结果的概念，将Web搜索结果扩展到包括图像和视频等多媒体对象，特定于意图的键值对以及允许用户直接与网页内容进行交互的元素从搜索结果页面。我们显示，用户明确地以及在其搜索行为中观察到时都表达了对增强结果的偏好。我们还展示了增强结果在帮助用户评估搜索结果的相关性方面的有效性。最后，我们证明了我们可以有效地生成增强的结果，以覆盖搜索结果页面的很大一部分。
答案 0 :(得分：2)
使用Object.entries()将对象转换为单词/索引对。使用Array.reduce()迭代条目。在reduce内部，使用Array.forEach()迭代索引，然后将每个单词分配给累加器（r）中的索引。用空格将单词数组连接起来。
const userdata = {"\"Ten":[0],"blue":[1],"links\"":[2],"have":[3],"defined":[4],"web":[5,36,65],"search":[6,32,37,70,90,108,126],"results":[7,33,38,71,82,99,119],"for":[8,80],"the":[9,28,56,61,69,95,105],"last":[10],"fifteen":[11],"years":[12],"--":[13],"snippets":[14],"of":[15,30,63,97,107,125],"text":[16],"combined":[17],"with":[18,60],"document":[19],"titles":[20],"and":[21,46,52,85],"URLs.":[22],"In":[23],"this":[24],"paper,":[25],"we":[26,111,114],"establish":[27],"notion":[29],"enhanced":[31,81,98,118],"that":[34,54,75,113],"extend":[35],"to":[39,58,103,120],"include":[40],"multimedia":[41],"objects":[42],"such":[43],"as":[44],"images":[45],"video,":[47],"intent-specific":[48],"key":[49],"value":[50],"pairs,":[51],"elements":[53],"allow":[55],"user":[57],"interact":[59],"contents":[62],"a":[64,78,122],"page":[66],"directly":[67],"from":[68],"page.":[72],"We":[73,92],"show":[74,112],"users":[76,102],"express":[77],"preference":[79],"both":[83],"explicitly,":[84],"when":[86],"observed":[87],"in":[88,100],"their":[89],"behavior.":[91],"also":[93],"demonstrate":[94],"effectiveness":[96],"helping":[101],"assess":[104],"relevance":[106],"results.":[109],"Lastly,":[110],"can":[115],"efficiently":[116],"generate":[117],"cover":[121],"significant":[123],"fraction":[124],"result":[127],"pages.":[128]};
const result = Object.entries(userdata)
.reduce((r, [word, indexes]) => {
indexes.forEach(index => r[index] = word);
return r;
}, [])
.join(' ');
console.log(result);
答案 1 :(得分：2)
您可以遍历该对象，然后
word）index中提供的职位（userdata[word]）arrResult[index] = word。然后，使用' '作为分隔符，将该数组连接到字符串中
例如：
var userdata = {"\"Ten":[0],"blue":[1],"links\"":[2],"have":[3],"defined":[4],"web":[5,36,65],"search":[6,32,37,70,90,108,126],"results":[7,33,38,71,82,99,119],"for":[8,80],"the":[9,28,56,61,69,95,105],"last":[10],"fifteen":[11],"years":[12],"--":[13],"snippets":[14],"of":[15,30,63,97,107,125],"text":[16],"combined":[17],"with":[18,60],"document":[19],"titles":[20],"and":[21,46,52,85],"URLs.":[22],"In":[23],"this":[24],"paper,":[25],"we":[26,111,114],"establish":[27],"notion":[29],"enhanced":[31,81,98,118],"that":[34,54,75,113],"extend":[35],"to":[39,58,103,120],"include":[40],"multimedia":[41],"objects":[42],"such":[43],"as":[44],"images":[45],"video,":[47],"intent-specific":[48],"key":[49],"value":[50],"pairs,":[51],"elements":[53],"allow":[55],"user":[57],"interact":[59],"contents":[62],"a":[64,78,122],"page":[66],"directly":[67],"from":[68],"page.":[72],"We":[73,92],"show":[74,112],"users":[76,102],"express":[77],"preference":[79],"both":[83],"explicitly,":[84],"when":[86],"observed":[87],"in":[88,100],"their":[89],"behavior.":[91],"also":[93],"demonstrate":[94],"effectiveness":[96],"helping":[101],"assess":[104],"relevance":[106],"results.":[109],"Lastly,":[110],"can":[115],"efficiently":[116],"generate":[117],"cover":[121],"significant":[123],"fraction":[124],"result":[127],"pages.":[128]};
let arrResult = [];
for (let word in userdata)
{
userdata[word].forEach((i) =>
{
arrResult[i] = word;
});
}
let result = arrResult.join(' ');
console.log(result);
答案 2 :(得分：0)
在您的情况下，您的数据就是属性名称本身，因此，最简单的方法是通过以下方式获取该名称：
var foo = Object.getOwnPropertyNames(userdata);
该函数返回数组中对象的所有属性名称，因此您只需将其加入：
foo.join(" ");
希望它适合您。
编辑
在这种情况下，上面的代码不是功能解决方案，没有考虑单词的索引。因此，提出解决方案的正确方法应该类似于Cid的答案（https://stackoverflow.com/a/55474582/9925983）：
const userdata = {"\"Ten":[0],"blue":[1],"links\"":[2],"have":[3],"defined":[4],"web":[5,36,65],"search":[6,32,37,70,90,108,126],"results":[7,33,38,71,82,99,119],"for":[8,80],"the":[9,28,56,61,69,95,105],"last":[10],"fifteen":[11],"years":[12],"--":[13],"snippets":[14],"of":[15,30,63,97,107,125],"text":[16],"combined":[17],"with":[18,60],"document":[19],"titles":[20],"and":[21,46,52,85],"URLs.":[22],"In":[23],"this":[24],"paper,":[25],"we":[26,111,114],"establish":[27],"notion":[29],"enhanced":[31,81,98,118],"that":[34,54,75,113],"extend":[35],"to":[39,58,103,120],"include":[40],"multimedia":[41],"objects":[42],"such":[43],"as":[44],"images":[45],"video,":[47],"intent-specific":[48],"key":[49],"value":[50],"pairs,":[51],"elements":[53],"allow":[55],"user":[57],"interact":[59],"contents":[62],"a":[64,78,122],"page":[66],"directly":[67],"from":[68],"page.":[72],"We":[73,92],"show":[74,112],"users":[76,102],"express":[77],"preference":[79],"both":[83],"explicitly,":[84],"when":[86],"observed":[87],"in":[88,100],"their":[89],"behavior.":[91],"also":[93],"demonstrate":[94],"effectiveness":[96],"helping":[101],"assess":[104],"relevance":[106],"results.":[109],"Lastly,":[110],"can":[115],"efficiently":[116],"generate":[117],"cover":[121],"significant":[123],"fraction":[124],"result":[127],"pages.":[128]};
let words = [];
Object.getOwnPropertyNames(userdata).forEach(propertyName =>
userdata[propertyName].forEach(value => words[value] = propertyName)
);
const text = words.join(' ');
console.log(text);
我认为他的答案仍然更具可读性和效率。