亲爱的,我做了一个javascript函数:选中了复选框以启用某些控制器,而未选中则禁用相同的控制器并清除其数据,仅在第一次单击时效果良好,这意味着如果我选中了该复选框并选择了数据,然后取消选中该复选框,它将清除输入框中的数据并隐藏datetimepicker。但是如果第二次选中该复选框并选择数据,则取消选中该复选框,它不会清除数据,但会隐藏时间选择器。
HTML
<div class="col-lg-12 col-md-12 col-sm-12 col-xs-12 margin-bottom-10 padding-none">
<div class="col-lg-3 col-md-3 col-sm-3 col-xs-12">
<div class="form-group">
<div class="form-check margin-top-30">
<label>
<input ng-model="attend" type="checkbox" name="check" ng-change="checkattendance()"> <span class="label-text">Attendance Time</span>
</label>
</div>
</div>
</div>
<div class="col-lg-3 col-md-3 col-sm-3 col-xs-12">
<div class="form-group">
<div class="col-xs-12">
<label class="control-label" for="name">Operator<span class="danger">*</span></label>
</div>
<div class="col-xs-12">
<select ng-disabled="!attend" ng-show="lang==0" class="form-control input-sm" ng-model="opinname" ng-options="o.opid as o.openm for o in Operator"></select>
<select ng-disabled="!attend" ng-show="lang==1" class="form-control input-sm" ng-model="opinname" ng-options="o.opid as o.opanm for o in Operator"></select>
</div>
</div>
</div>
<div class="col-lg-3 col-md-3 col-sm-6 col-xs-6">
<div class="form-group">
<div class="col-xs-12">
<label class="control-label" for="name">From <span class="danger">*</span></label>
</div>
<div class="col-xs-12 date">
<div id="timeform1" class="input-append date">
<input data-format="hh:mm:ss" type="text" class="form-control" ng-disabled="!attend" ng-model="from2">
<span class="add-on" >
<i data-time-icon="icon-time"id="icon1" data-date-icon="icon-calendar" ng-show="attend">
</i>
</span>
</div>
</div>
</div>
</div>
<div class="col-lg-3 col-md-3 col-sm-6 col-xs-6">
<div class="form-group">
<div class="col-xs-12">
<label class="control-label" for="name">To <span class="danger">*</span></label>
</div>
<div class="col-xs-12 date">
<div id="timeto1" class="input-append date">
<input data-format="hh:mm:ss" type="text" class="form-control" ng-disabled="!attend" ng-model="to2">
<span class="add-on">
<i data-time-icon="icon-time" data-date-icon="icon-calendar" ng-show="attend">
</i>
</span>
</div>
</div>
</div>
</div>
Angular js
$scope.checkattendance = function () {
if ($scope.attend == true) {
$('#timeform1').datetimepicker({
pickTime: true, pickDate: false
});
$('#timeto1').datetimepicker({
pickTime: true, pickDate: false
});
}
else {
$scope.opinname = '';
$scope.from2 = '';
$scope.to2 = '';
$scope.apply();
}
}
为什么未绑定ng-model = from2和ng-model = to2并清除数据 任何帮助,在此先感谢
答案 0 :(得分:0)
一个问题是您当前的checkattendance函数没有更改出席布尔值,因此每次更改复选框时都需要将状态从true切换为false或从false切换为true,一种简单的修改是修改功能并添加{ {1}}在函数的开头或结尾。如下所示:
$scope.attend =!$scope.attend;
您还应该将复选框的选定状态绑定到该布尔值,例如$scope.checkattendance = function () {
$scope.attend =!$scope.attend;
if ($scope.attend == true) {
$('#timeform1').datetimepicker({
pickTime: true, pickDate: false
});
$('#timeto1').datetimepicker({
pickTime: true, pickDate: false
});
}
else {
$scope.opinname = '';
$scope.from2 = '';
$scope.to2 = '';
$scope.apply();
}
}