Symfony4定制路由器UrlGenerator

Question

我要自定义路由UrlGenerator

以下是我的修改

File: vendor/symfony/framework-bundle/Resources/config/routing.xml

<argument key="generator_class">Symfony\Component\Routing\Generator\UrlGenerator</argument>
<argument key="generator_base_class">Symfony\Component\Routing\Generator\UrlGenerator</argument>

到

<argument key="generator_class">App\Routing\UrlGenerator</argument>
<argument key="generator_base_class">App\Routing\UrlGenerator</argument>

UrlGenerator类

<?php

namespace App\Routing;

class UrlGenerator extends \Symfony\Component\Routing\Generator\UrlGenerator
{

    protected function doGenerate($variables, $defaults, $requirements, $tokens, $parameters, $name, $referenceType, $hostTokens, array $requiredSchemes = [])
    {
        $url = parent::doGenerate($variables, $defaults, $requirements, $tokens, $parameters, $name, $referenceType, $hostTokens, $requiredSchemes);
        var_dump($url);
        die;
    }
}

控制器文件

<?php

namespace App\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\AbstractController;
use Symfony\Component\Routing\Annotation\Route;

class DefaultController extends AbstractController
{

    /**
     * @Route("/test")
     */
    public function test()
    {
        $ret = $this->generateUrl('_profiler_exception_css', ['token' => 'test']);
        var_dump($ret);
        die;
    }
}

他似乎是可以工作的，但是我认为这不是最好的方法，能帮帮我，如何配置，不要修改作曲家内部的代码