Question

我想合并2个数组：

arr1 = [["apple"], ["banana", "cherry"]]
arr2 = ["id1", "id2"]

我想得到如下输出：

result = [["apple id1"], ["banana id2", "cherry id2"]]

或

result = [["apple from id1"], ["banana from id2", "cherry from id2"]]

我尝试了concat，但这并没有为我保留每个元素的ID。我总体上是新手，到目前为止，我还没有找到任何能给我适当输出的结果。有什么提示我该怎么做？

Answer 1

您可以映射新项目。

from bokeh.models import ColumnDataSource, HoverTool, CustomJS
from bokeh.plotting import show, figure

source = ColumnDataSource(dict(x = [1, 2], y = [3, 4], color = ['blue', 'blue']))
p = figure(tools = 'hover')
c = p.circle(x = 'x', y = 'y', color = 'color', size = 20, source = source)

code = '''  if (cb_data.index.indices.length > 0){ 
                selected_index = cb_data.index.indices[0];

                for (index in source.data['color']){
                    if (index == selected_index)
                        source.data['color'][index] = 'red';
                    else
                        source.data['color'][index] = 'yellow';             
                source.change.emit();
            }
            else{
                for (index in source.data['color'])
                    source.data['color'][index] = 'blue';
            } '''
p.select(HoverTool).callback = CustomJS(args = dict(source = source), code = code)
show(p)

Answer 2

Array#map是您所需要的。

arr1 = [["apple"], ["banana", "cherry"]]
arr2 = ["id1", "id2"]

var result = arr2.map((id, idx) => {
  return arr1[idx].map(item => item + " from " + id);
})

console.log(result);

Answer 3

这样的功能会起作用

function concat(arr1, arr2) {
    for (let i = 0; i < arr1.length; i++) {
        for (let j = 0; j < arr1[i].length; j++) {
            arr1[i][j] += ` ${arr2[i]}`;
        }
    }

    return arr1;
}

您可以像执行

concat([["apple"], ["banana", "cherry"]], ["id1", "id2"])

注意：这会修改arr1，因为它已作为参考传递。您可以更改此设置，以便根据需要使用它的副本。

Answer 4

简单的循环，并将“ from”添加到结果中。

arr1 = [["apple"], ["banana", "cherry"]];
arr2 = ["id1", "id2"];


for (var i = 0; i < arr1.length; i++){
  
  arr1[i] = arr1[i].join() + " from " + arr2[i]

}

console.log(arr1);

如何基于索引连接2个数组

4 个答案: