Question

我想收集所有应用程序的所有模型，然后过滤它们，但出现以下错误：

AttributeError at /search 'list' object has no attribute 'filter'
Request Method: GET Request
URL:    http://127.0.0.1:8000/search?category=1&submit=%D9%BE%DB%8C%D8%AF%D8%A7+%DA%A9%D9%86%21
Django Version: 2.1.7 Exception Type:   AttributeError Exception Value: 
'list' object has no attribute 'filter' Exception

views.py

from django.shortcuts import render
from app_adventure.models import *
from app_cultural.models import *
from app_children.models import *
from app_base.choices import Tour_type_choices, Destination_choices, Day_choices, Month_choices
from itertools import chain


# Create your views here.


# search


def search(request):
    adventure = AdventureTor.objects.all()
    cultural = CulturalTor.objects.all()
    children = ChildTor.objects.all()
    queryset_list = list(chain(adventure, cultural, children))

    # search by category
    if 'category' in request.GET:
        category = request.GET['category']
        if category:
            queryset_list = queryset_list.filter(category__icontains=category)  # mitonest iexact bashe

    context = {
        'Tour_type_choices': Tour_type_choices,
        'Destination_choices': Destination_choices,
        'Day_choices': Day_choices,
        'Month_choices': Month_choices,
        'search': queryset_list,
    }

    return render(request, 'search/search.html', context)

Answer 1

您无法过滤链，因为它不再是SQL查询。您可以尝试分别过滤这3个查询，然后使用chain()。例如：

def search(request):
    my_queries = [AdventureTor.objects.all(),
                  CulturalTor.objects.all(),
                  ChildTor.objects.all()]

    # search by category
    if 'category' in request.GET:
        category = request.GET['category']
        if category:
            my_queries = [query.filter(category__icontains=category) 
                          for query in my_queries]

    queryset_list = list(chain(**my_queries))
    context = {
    ...

Answer 2

如错误所述，请在添加前过滤查询集

django链表对象过滤器

2 个答案: