我已经问过我周围的人，并无数次地尝试获取此修复程序。该程序应该能够根据需要多次添加用户的网站和密码，并显示他们选择的网站和密码。
现在，当您以是回答import numpy as np
autoenc_model.fit(np.ones((5,128,128,3)), np.ones((5,128,128,3)))
dec_model.predict(np.ones((1,8,8,2)))
时，它并不需要输入新的网站名称和密码，而只是重复问题--no-banner，即使您有输入网站名称和密码，并用否回答would you like to add another website?，然后选择选项1以查看现有帐户，然后重复would you like to add another website?，甚至在选项1处出现< / p>
输入及其应如何输出：
1）查找现有密码
2）为您的应用保存新密码
3）查看密码柜的摘要
4）成功退出密码柜 1
您没有存储的网站和密码
1）查找现有密码
2）为您的应用保存新密码
3）查看密码柜的摘要
4）成功退出密码柜 2
您要添加的网站/应用的名称是什么？ instagram
您的{instagram}帐户的密码是什么？ bob91
您要添加其他网站吗？ 是
您要添加的网站/应用的名称是什么？ facebook
您的{facebook}帐户的密码是什么？ bob92
您要添加其他网站吗？ 否
1）查找现有密码
2）为您的应用保存新密码
3）查看密码柜的摘要
4）成功退出密码柜 1
输入您要为 instagram
查找密码的应用
网站名称= instagram
密码= bob91
完整代码：
would you like to add another website?答案 0 :(得分：1)
您的代码不起作用，因为您没有从break循环中while True:进入
while True: ask_again = input('''Would you like to add another app and password?''') if ask_again.lower() == "yes": locker_menu_var = "2" <--- does not leave while loop elif ask_again.lower() == "no": locker_menu_func() else: # etc.
将您的方法缩小并处理一个问题以简化控制流程，例如：
vault_apps = {}
# ,2,Hallo,Yuhu,y,Hallo2,Yuh,n,3,4
def menu():
print('\n'+'-'*40)
print('1) find your existing passwords')
print('2) save a new password for your apps')
print('3) see a summary of your password locker')
print('4) exit password locker successfully')
print('-'*40)
k = None
while k not in {"1","2","3","4"}:
k = input("Choose: ")
return int(k) # return the number chosen
def input_new_app():
global vault_apps
app = None
while not app:
app = input("What is your apps name? ")
pw = None
while not pw:
pw = input("What is your apps passphrase? ")
vault_apps[app]=pw
def print_vault():
print("Vault content:")
for key,value in vault_apps.items():
print(f" {key:<10}\t==>\t{value}")
def find_password():
if vault_apps:
pass
else:
print("nothing in your password store")
def main():
k = None
print('You have opened the locker,\nPlease select what you would like to do.')
while True:
choice = menu()
if choice == 1:
find_password()
elif choice == 2:
input_new_app()
k = input("Would you like to add another app and password?").lower()
while k in {"yes","y"}:
input_new_app()
elif choice == 3:
print_vault()
elif choice == 4:
print("Good bye")
break
main()
输出：
You have opened the locker,
Please select what you would like to do.
----------------------------------------
1) find your existing passwords
2) save a new password for your apps
3) see a summary of your password locker
4) exit password locker successfully
----------------------------------------
Choose: 1
nothing in your password store
----------------------------------------
1) find your existing passwords
2) save a new password for your apps
3) see a summary of your password locker
4) exit password locker successfully
----------------------------------------
Choose: 2
What is your apps name? A
What is your apps passphrase? 66
Would you like to add another app and password? n
----------------------------------------
1) find your existing passwords
2) save a new password for your apps
3) see a summary of your password locker
4) exit password locker successfully
----------------------------------------
Choose: 3
Vault content:
A ==> 66
----------------------------------------
1) find your existing passwords
2) save a new password for your apps
3) see a summary of your password locker
4) exit password locker successfully
----------------------------------------
Choose: 4
Good bye
答案 1 :(得分：0)
这种逻辑是有缺陷的。 一旦进入无限while循环，就只能输入“ no”来退出它。输入“是”时，locker_menu_var的值会更改，但不会退出循环，因此它将继续重复相同的菜单。
while True:
ask_again = input('''Would you like to add another app and password?
''')
if ask_again.lower() == "yes":
locker_menu_var = "2"
elif ask_again.lower() == "no":
locker_menu_func()
您正在混合循环和递归，这使事情变得混乱。一种简单的方法是：
vault_apps = []
def locker_menu():
# the entry message
msg = '''You have opened the locker, Please select what you would like to do,'''
print(msg, end="\n\n")
# nume options
menu = ["1) find your existing passwords",
"2) save a new password for your apps",
"3) see a summary of your password locker",
"4) exit password locker successfully"]
menu_string = f"Press:\n{menu[0]}\n{menu[1]}\n{menu[2]}\n{menu[3]}\n"
# now enter the loop
while True:
# input variable
# NOTE: This variable is inside the loop,
# so that the user can enter the value everytime
# the loop repeates.
locker_menu_var = input(menu_string)
if locker_menu_var == "1":
# retrieve password for an existing record.
# although it's not a good idea to just print
# all the records, I am not changing your application logic
# because I don't see any use in it.
# you missed one case in your logic,
# which I have fixed here.
if len(vault_apps) == 0:
print("you have nothing stored")
else:
print(vault_apps)
elif locker_menu_var == "2":
# for a new entry
# enter your logic here
an = input("app name: ")
passw = input("password: ")
vault_apps.append([an, passw])
done = False # flag for exiting
while not done:
inp = input("enter another?")
if inp == "yes":
# enter logic here
an = input("app name: ")
passw = input("password: ")
vault_apps.append([an, passw])
else:
done = True
elif locker_menu_var == "3":
# do something
pass
elif locker_menu_var == "4":
return
if __name__ == "__main__":
locker_menu()