Question

我正试图在Groovy中为我的Jenkins职位之一生成以下JSON输出。

期望的JSON

 {
    "svc-a": {
        "type": "object",
        "properties": {
            "svcVersion": {
                "type": "string",
                "propertyOrder": 1,
                "enum": ["No build", "1.0.0.59", "1.0.0.58"]
            },
            "skipConfigs": {
                "type": "boolean",
                "format": "checkbox"
            }
        }
    },
    "svc-b": {
        "type": "object",
        "properties": {
            "svcVersion": {
                "type": "string",
                "propertyOrder": 1,
                "enum": ["No build", "1.0.0.177", "1.0.0.176", "1.0.0.175"]
            },
            "skipConfigs": {
                "type": "boolean",
                "format": "checkbox"
            }
        }
    }
 }

我正在遍历每个服务，并从Jenkins获取内部版本号。对于每个服务，我试图生成json以及一些其他标头，并将其附加到地图。最后，从地图构建json对象时，将json视为字符串。

MyCode。

#!/usr/bin/env groovy
import org.boon.Boon;
import groovy.json.JsonSlurper;
import groovy.transform.Field;
import groovy.json.JsonBuilder;
import groovy.json.*

def serviceList = [
"svc-a",
"svc-b"
]

def getBuildVersions(serviceName) {

  def resultList = []
  resultList.add(0,"No build")
       def job = jenkins.model.Jenkins.instance.getAllItems().findAll { it.name.contains(serviceName) }

  job.each { s ->
    if (s.toString().contains("")) {
      print s
       def builds = s.getBuilds()
       builds.each { t->
         if((t.result).toString() == "SUCCESS" && !t.displayName.contains("SNAPSHOT") && !t.displayName.contains("config")){
              resultList.add(t.displayName)
         }
      }
    }
  }

  return resultList
}

def retVal = new HashMap<String, Map>()

for (svc in serviceList) {

  def myBuilds = getBuildVersions(svc)

  List ver = myBuilds.collect{ "'" + it + "'"}

  def header = """
{"type": "object", "properties": { "svcVersion": { "type": "string", "propertyOrder": 1, "enum": $ver }, "skipConfigs": { "type": "boolean", "format": "checkbox" } } }
"""

def json = JsonOutput.toJson(header)
def result = new JsonSlurper().parseText(json)
  // s =  "'" + svc + "'"
  retVal.put(svc, result)

}


def builder = new JsonBuilder()

sjson =  JsonOutput.toJson(retVal)

return sjson

接收到的输出

{"svc-a":"\n{\"type\": \"object\", \"properties\": { \"svcVersion\": { \"type\": \"string\", \"propertyOrder\": 1, \"enum\": ['No build', '1.0.0.59', '1.0.0.58', '1.0.0.57', '1.0.0.56', '1.0.0.55', '1.0.0.54', '1.0.0.53', '1.0.0.52', '1.0.0.51', '1.0.0.49', '1.0.0.48', '1.0.0.47', '1.0.0.46', '1.0.0.45', '1.0.0.38', '1.0.0.37', '1.0.0.36', '1.0.0.35', '1.0.0.33', '1.0.0.31', '1.0.0.30', '1.0.0.29', '1.0.0.28', '1.0.0.27', '1.0.0.26', '1.0.0.25', '1.0.0.24', '1.0.0.22', '1.0.0.20', '1.0.0.19', '1.0.0.18', '1.0.0.17', '1.0.0.16', '1.0.0.13', '1.0.0.11', '1.0.0.8', '1.0.0.6', '1.0.0.5'] }, \"skipConfigs\": { \"type\": \"boolean\", \"format\": \"checkbox\" } } }\n","svc-b":"\n{\"type\": \"object\", \"properties\": { \"svcVersion\": { \"type\": \"string\", \"propertyOrder\": 1, \"enum\": ['No build', '1.0.0.177', '1.0.0.176', '1.0.0.175', '1.0.0.173', '1.0.0.172', '1.0.0.171', '1.0.0.170', '1.0.0.169', '1.0.0.167', '1.0.0.166', '1.0.0.165', '1.0.0.164', '1.0.0.163', '1.0.0.162', '1.0.0.158', '1.0.0.156', '1.0.0.38', '1.0.0.37', '1.0.0.36', '1.0.0.35', '1.0.0.33', '1.0.0.31', '1.0.0.29', '1.0.0.27'] }, \"skipConfigs\": { \"type\": \"boolean\", \"format\": \"checkbox\" } } }\n"}

当Groovy Map转换为JSON时，会将json对象中的值视为一个字符串。

如何获取格式正确的json输出。我来自python背景，在Groovy上没有mcuh的想法。

Answer 1

仅通过字符串操作即可找到解决方案

for (svc in serviceList) {

  def myBuilds = getBuildVersions(svc)

  List ver = myBuilds.collect{ '"' + it + '"'}

  def header = """
"$svc": {"type": "object", "properties": { "svcVersion": { "type": "string", "propertyOrder": 1, "enum": $ver }, "skipConfigs": { "type": "boolean", "format": "checkbox" } } }
"""
  if (firstRun == "true"){
    retVal =  header
  } else {
    retVal = retVal + "," + header
  }
   firstRun = "false"
}

Groovy无法根据需要生成json输出

1 个答案: