Question

我的任务是检查加倍单词列表，并将结果输出到字典中。

首先，我试图执行以下代码：

for word in wordsList:
    for letter in word:
        if word[letter] == word[letter+1]:

但是只要我有一个错误，我就会对其进行一些更改：

wordsList = ["creativity", "anna", "civic", "apology", "refer", "mistress", "rotor", "mindset"]
dictionary = {}

for word in wordsList:
    for letter in range(len(word)-1):
        if word[letter] == word[letter+1]:
            dictionary[word] = ("This word has a doubling")
        else:
            dictionary[word] = ("This word has no doubling")
print(dictionary)

现在它可以工作，但是不能正常工作。我真的需要建议！预先感谢

我希望输出 {creativity：“这个词不会加倍”}，{anna：“这个病房会加倍”}等等。

Answer 1

wordsList = ["creativity", "anna", "civic", "apology", "refer", "mistress", "rotor", "mindset"]
dictionary = {}

for word in wordsList:
    for index, char in enumerate(word[:-1]):    # Take one less to prevent out of bounds
        if word[index + 1] == char:             # Check char with next char
            dictionary[word] = True
            break                               # The one you forgot, with the break you wouldnt override the state
    else:
        dictionary[word] = False

print(dictionary)

您忘记了break语句；循环将继续并覆盖您找到的结论。我对您的原因做了自己的实现。

Answer 2

wordsList = ["creativity", "anna", "civic", "apology", "refer", "mistress", "rotor", "mindset"]
dictionaries = []
for word in wordsList: #for example:creativity
    alphabets=[]
    for x in word:
        alphabets+=x #now alphabets==['c','r','e','a','t','i','v','i','t','y']
    num=0
    while True:
        x=alphabets[0]  #for example 'c'
        alphabets.remove(x)  #now alphabets==['r','e','a','t','i','v','i','t','y']
        if x in alphabets:  # if alphabets contain 'c'
            doubling=True   # it is doubling
            break                
        else:
            doubling=False  #continue checking
            if len(alphabets)==1:  #if there is only one left
                break              #there is no doubling
    if doubling:
        dictionaries.append({word:"This word has a doubling"})
    else:
        dictionaries.append({word:"This word has no doubling"})
print(dictionaries)

如何找到一个词加倍？

2 个答案: