Question

我正在使用Python读取文件，我只想提取与某些内容匹配的行。 '\ 我的问题是：如果我只传递一个字符串来进行比赛，我就能做到（就像下面的代码一样）'

import sys,os
import re
import pandas as pd

path = 'file'
sports = ['Sports', 'Nature']
keyword = 'Sports'
data = pd.DataFrame([])

with open(path) as auto:
  for line in auto:
    if keyword in line:
        print(line)

我传递了一个列表，但我无法检索到任何行：

with open(path) as auto:
  for line in auto:
    if any(x in errors for x in line):
        print(line)

有人知道我该怎么做吗？

Answer 1

当您遍历str和list时，请注意区别，

>>> keyword = ['sports', 'something else']
>>> line = "line that has a word sports in it"
>>> 'sports' in line
True
>>> any(x in keyword  for x in line.split()) # iterating over list
True
>>> any(x in keyword  for x in line) # iterating over each characters in an string
False

Answer 2

您可以使用列表理解功能来替代：

file = [line.lower() for line in open(path).readlines()]
required_line = [line for text in keyword for line in file if text.lower() in line]

通过您的方法，您错过了任何东西：

with open(path) as auto:
    for line in auto:
        if any(x for x in keyword for x in line):
            print(lines)

读取文件-与列表匹配行

2 个答案: