Question

我正在服务器上设置Java Web应用程序，但其余控制器显示 404错误。

在我的本地系统上一切正常。

这是我在Java hibernate spring中的第一个项目。

下面是我的代码：

UserLoginController.java

package org.jasyatra.controller;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RestController;
import org.jasyatra.model.User;
import org.jasyatra.model.LoginAuthToken;
import org.jasyatra.service.UserLoginService;
import org.jasyatra.service.LoginAuthTokenService;

@RestController
public class UserLoginController {

    @Autowired
    UserLoginService userLoginService;

    @Autowired
    LoginAuthTokenService loginAuthTokenService;

    @RequestMapping(value = "/user/login", method = RequestMethod.POST, headers = "Accept=application/json")
    public Map login(@RequestBody User parameters) {
        List<User> loginResponse = userLoginService.login(parameters);

        Map<String, String> response = new HashMap<>();

        if (loginResponse.size() > 0) {
            response.put("result", "true");
            response.put("id", Integer.toString(loginResponse.get(0).getId()));
            response.put("type", loginResponse.get(0).getType());
            response.put("firstName", loginResponse.get(0).getFirstName());
            response.put("lastName", loginResponse.get(0).getLastName());
            response.put("permissions", loginResponse.get(0).getPermissions());
            List<LoginAuthToken> responseToken = loginAuthTokenService.getLatestToken(loginResponse.get(0).getId(),loginResponse.get(0).getType());
            response.put("token", responseToken.get(0).getToken());
        } else {
            response.put("result", "false");
            response.put("message", "Invalid mobile no or password!");
        }

        return response;
    }
}

UserLoginDAO.java

package org.jasyatra.dao;

import java.util.List;
import org.hibernate.Query;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.jasyatra.model.User;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Repository;
import org.jasyatra.service.HashService;

@Repository
public class UserLoginDAO {

    @Autowired
    private SessionFactory sessionFactory;

    public List<User> login(User parameters) {
        Session session = this.sessionFactory.getCurrentSession();

        Query query = session.createQuery("from User where mobileNo=:mobileNo and password=:password and status=:status");
        query.setParameter("mobileNo", parameters.getMobileNo());
        query.setParameter("password", HashService.getHash(parameters.getPassword(), "SHA1"));
        query.setParameter("status", "active");
        List<User> response = query.list();
        return response;
    }
}

UserLoginService.java

package org.jasyatra.service;

import java.nio.charset.Charset;
import java.util.Date;
import java.util.List;
import java.util.Random;
import org.jasyatra.dao.UserLoginDAO;
import org.jasyatra.dao.LoginAuthTokenDAO;
import org.jasyatra.model.LoginAuthToken;
import org.jasyatra.model.User;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;

@Service
public class UserLoginService {

    @Autowired
    UserLoginDAO userLoginDao;

    @Autowired
    LoginAuthTokenDAO loginAuthTokenDAO;

    @Autowired
    LoginAuthTokenService loginAuthTokenService;

    @Transactional
    public List<User> login(User parameters) {

        List<User> login = userLoginDao.login(parameters);
        LoginAuthToken loginAuthToken = new LoginAuthToken();
        if (login.size() > 0 && login.get(0).getId() > 0) {
            try {

                loginAuthToken.setLoginId(login.get(0).getId());
                loginAuthToken.setLoginType(login.get(0).getType());

                byte[] array = new byte[7]; // length is bounded by 7
                new Random().nextBytes(array);
                String generatedString = new String(array, Charset.forName("UTF-8"));

                String token = HashService.getHash(generatedString, "SHA1");
                loginAuthToken.setDateCreated(new Date());
                loginAuthToken.setToken(token);
                loginAuthTokenService.save(loginAuthToken);
            } catch (Exception e) {
                e.printStackTrace();
            }
        }

        return login;
    }
}

context.xml

<?xml version="1.0" encoding="UTF-8"?>
<Context path="/"/>

spring-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans"
             xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
             xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd">

    <annotation-driven />

    <resources mapping="/resources/**" location="/resources/" />

    <beans:bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
        <beans:property name="driverClassName" value="com.mysql.jdbc.Driver" />
        <beans:property name="url" value="jdbc:mysql://localhost:3306/jasyatra" />
        <beans:property name="username" value="root" />
        <beans:property name="password" value="" />
    </beans:bean>

    <!-- Hibernate 4 SessionFactory Bean definition -->
    <beans:bean id="hibernate4AnnotatedSessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
        <beans:property name="dataSource" ref="dataSource" />
        <beans:property name="annotatedClasses">
            <beans:list>
                <beans:value>org.jasyatra.model.User</beans:value>
            </beans:list>
        </beans:property>
        <beans:property name="hibernateProperties">
            <beans:props>
                <beans:prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</beans:prop>
                <beans:prop key="hibernate.show_sql">true</beans:prop>
            </beans:props>
        </beans:property>
    </beans:bean>
    <beans:bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
        <beans:property name="maxUploadSize" value="268435456"/>
    </beans:bean>
    <context:component-scan base-package="org.jasyatra" />

    <tx:annotation-driven transaction-manager="transactionManager"/>

    <beans:bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager">
        <beans:property name="sessionFactory" ref="hibernate4AnnotatedSessionFactory" />
    </beans:bean>
</beans:beans>

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    version="3.0">
    <display-name>Archetype Created Web Application</display-name>
    <servlet>
 <servlet-name>spring</servlet-name>
 <servlet-class>
  org.springframework.web.servlet.DispatcherServlet
 </servlet-class>
 <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
 <servlet-name>spring</servlet-name>
 <url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>

我遇到的主要问题是，它能够运行index.jsp，但不能运行控制器。可能是什么问题？

请指引我正确的方向。

谢谢

Answer 1

您无法在浏览器中打开该URL，因为它是POST服务，您只能在浏览器中打开GET URL。您需要在点击该网址的同时添加正文以进行测试您的服务可以使用邮递员。

Answer 2

    no need to send "Accept" header this way, you can use however following attribute instead if you expect a json body with the post request :

    @RequestMapping(value = "/user/login", method = RequestMethod.POST, consumes=MediaType.APPLICATION_JSON_VALUE);

if you want to get "Accept" header value of your request you can get it like : 
    public Map login(@RequestBody User parameters,@RequestHeader(value="Accept") String accept){  
    ....

Java控制器在实时服务器上显示404错误

2 个答案: