我正在尝试将编译时间字符串与枚举值相关联。
这是我第一次尝试解决该问题:
EnumValue将在字符串和枚举之间进行编译时关联
template<typename EnumType, int EnumIntValue, const char* EnumStrValue>
class EnumValue
{
public:
static const char* toString()
{
return EnumStrValue;
}
static const int toInt()
{
return EnumIntValue;
}
static EnumType get()
{
return static_cast<EnumType>(EnumIntValue);
}
};
EnumValueHolder将保存字符串和枚举的实际值。 我不喜欢当前的设计,因为它仍然需要持有一个指向字符串的指针。为此,我更希望使用编译时间关联,但是无法提出更优雅的解决方案
template<typename EnumType>
class EnumValueHolder
{
public:
EnumValueHolder()
{}
EnumValueHolder(const EnumType& value, const char* str)
: value(value), str(str)
{}
bool operator==(const EnumValueHolder<EnumType>& rhs) { return value == rhs.value; }
bool operator==(const EnumType& rhs)const { return value == rhs; }
operator EnumType()const
{
return value;
}
const char* toString()const
{
return str;
}
const int toInt()const
{
return static_cast<int>(value);
}
private:
EnumType value;
char const* str;
};
Marcos可以轻松地引用枚举类型和枚举值持有者的构造
#define ENUM_VALUE_TYPE(enumName, enumValue) \
EnumValue<enumName, (int)enumName::enumValue, str_##enumValue>
#define ENUM_VALUE_MAKE(enumName, enumValue) \
EnumValueHolder<enumName> { \
ENUM_VALUE_TYPE(enumName, enumValue)::get(), \
ENUM_VALUE_TYPE(enumName, enumValue)::toString() }
以下是我的测试用例和用法示例:
const char str_Apple[] = "Apple";
const char str_Orange[] = "Orange";
const char str_Pineapple[] = "Pineapple";
enum class EFruits
{
Apple,
Orange,
Pineapple
};
int main()
{
auto evApple = ENUM_VALUE_MAKE(EFruits, Apple);
std::cout << evApple.toString() << std::endl;
auto evOrange = ENUM_VALUE_MAKE(EFruits, Orange);
std::cout << evOrange.toString() << std::endl;
std::cout << "compare: " << (evApple == evOrange) << std::endl;
evApple = evOrange;
std::cout << evApple.toString() << std::endl;
auto myfruit = ENUM_VALUE_MAKE(EFruits, Pineapple);
std::cout << myfruit.toString() << std::endl;
switch (myfruit)
{
case EFruits::Apple:
std::cout << "Im an apple!" << std::endl;
break;
case EFruits::Orange:
std::cout << "Im an Orange!" << std::endl;
break;
case EFruits::Pineapple:
std::cout << "Im a Pineapple!" << std::endl;
break;
default:break;
}
}
目标之一是删除全局字符串:
const char str_Apple[] = "Apple";
const char str_Orange[] = "Orange";
const char str_Pineapple[] = "Pineapple";
另一种方法是创建一个将枚举与字符串相关联的宏
//Some crazy define that makes pairs of enum values and strings as
//compile time constants
#define DEFINE_ENUM_STRING(enumValue)\
enumValue, #enumValue
//Ideally, the macro would be used like this. This should be usable in any
//scope (global, namespace, class)
//with any access specifier (private, protected, public)
enum class EFruits
{
DEFINE_ENUM_STRING(Apple),
DEFINE_ENUM_STRING(Orange),
DEFINE_ENUM_STRING(Pineapple)
};
所以有两个主要问题:
1)这种当前的设计是否真的可以保证将枚举与字符串相关联的编译时间常数?
2)如何定义宏以对枚举值进行字符串化,并使用1行在枚举类中声明该值?
编辑:这应该可以在使用c ++ 11的win64平台上与msvs2017一起工作并编译。
谢谢。
答案 0 :(得分:1)
我认为它应该与MSVC2017一起使用。它在constexpr函数中使用C ++ 14,但是您可以将它们拆分为单个return语句constexprs以与C ++ 11兼容(但是MSVC2017支持C ++ 14)。
EnumConverter存储每个枚举项的char *,枚举和字符串哈希值。对于每个枚举,您必须专门EnumConverter::StrEnumContainer
。枚举字符串对可以使用您指定的类似宏来生成。
#include <tuple>
#include <array>
#include <stdexcept>
using namespace std;
enum ELogLevel {
Info,
Warn,
Debug,
Error,
Critical
};
static constexpr size_t constexprStringHash( char const* const str ) noexcept
{
return (
( *str != 0 ) ?
( static_cast< size_t >( *str ) + 33 * constexprStringHash( str + 1 ) ) :
5381
);
}
class EnumConverter final
{
public:
EnumConverter() = delete;
EnumConverter( const EnumConverter& ) = delete;
EnumConverter( EnumConverter&& ) = delete;
EnumConverter& operator =( const EnumConverter& ) = delete;
EnumConverter& operator =( EnumConverter&& ) = delete;
template< typename ENUM_T >
static constexpr const char* toStr( const ENUM_T value )
{
const auto& strEnumArray{ StrEnumContainer< ENUM_T >::StrEnumPairs };
const char* result{ nullptr };
for( size_t index{ 0 }; index < strEnumArray.size(); ++index ) {
if( std::get< 1 >( strEnumArray[ index ] ) == value ) {
result = std::get< 0 >( strEnumArray[ index ] );
break;
}
}
return ( ( result == nullptr ) ? throw std::logic_error{ "Enum toStrBase conversion failed" } : result );
}
template< typename ENUM_T >
static constexpr ENUM_T fromStr( const char* const str )
{
const auto& strEnumArray{ StrEnumContainer< ENUM_T >::StrEnumPairs };
const size_t hash{ constexprStringHash( str ) };
const ENUM_T* result{ nullptr };
for( size_t index{ 0 }; index < strEnumArray.size(); ++index ) {
if( std::get< 2 >( strEnumArray[ index ] ) == hash ) {
result = &( std::get< 1 >( strEnumArray[ index ] ) );
}
}
return ( ( result == nullptr ) ? throw std::logic_error{ "Enum toStrBase conversion failed" } : *result );
}
private:
template< typename ENUM_T, size_t LEN >
using ARRAY_T = std::array< std::tuple< const char* const, const ENUM_T, const size_t >, LEN >;
template< typename ENUM_T >
static constexpr std::tuple< const char* const, ENUM_T, size_t > getTuple( const char* const str, const ENUM_T type ) noexcept
{
return std::tuple< const char* const, ENUM_T, size_t >{ str, type, constexprStringHash( str ) };
}
template< typename ENUM_T >
struct StrEnumContainer
{
};
template< typename ENUM_T >
friend struct StrEnumContainer;
};
template<>
struct EnumConverter::StrEnumContainer< ELogLevel >
{
using ENUM_T = ELogLevel;
static constexpr EnumConverter::ARRAY_T< ENUM_T, 5 > StrEnumPairs{ {
{ getTuple( "Info", ENUM_T::Info ) },
{ getTuple( "Warn", ENUM_T::Warn ) },
{ getTuple( "Debug", ENUM_T::Debug ) },
{ getTuple( "Error", ENUM_T::Error ) },
{ getTuple( "Critical", ENUM_T::Critical ) },
} };
};
int main()
{
//static_assert( EnumConverter::fromStr< ELogLevel >( "Info" ) == EnumConverter::fromStr< ELogLevel >( EnumConverter::toStr( Error ) ), "Error" ); // Error
static_assert(
EnumConverter::toStr( Warn )[ 0 ] == 'W' &&
EnumConverter::toStr( Warn )[ 1 ] == 'a' &&
EnumConverter::toStr( Warn )[ 2 ] == 'r' &&
EnumConverter::toStr( Warn )[ 3 ] == 'n',
"Error"
);
static_assert( EnumConverter::fromStr< ELogLevel >( "Info" ) == EnumConverter::fromStr< ELogLevel >( EnumConverter::toStr( Info ) ), "Error" );
}