Question

#Python 3.7.2所以我是新手，只是希望我的程序在两个随机数都匹配的情况下运行“ True”，而在两个都不匹配的情况下运行“ False”，这对于每个人来说似乎都是非常基础的，但是我我慢...

def firstSet():
  import random
  for x in range(1):
    return(random.randint(1,10))

def secondSet():import random
  for x in range(1):
    return(random.randint(1,10))

def view():
  return(secondSet(), firstSet())

def theMatch():
  if secondSet() == firstSet():
    return(True, view())
  else:
    return(False, view())

print(theMatch()) 


theMatch()

我希望输出类似于(True, (5, 5))或(False, (2,3))，但实际输出通常像(True, (10, 2))或(False, (7,7))一样，只是完全随机。我知道有很多方法可以用更简单的方式编写此程序，但只是想知道我哪里出了错。谢谢

Answer 1

欢迎堆栈溢出。

您的代码无法正常运行的原因是，您实际上多次多次计算“随机”值，包括之后，您检查它们是否匹配，然后在进行重新计算之前您打印。

让我们稍微看一下代码：
当您调用theMatch（）时，会发生以下情况：

如果secondset（）== firstset（）：在这里，您正在计算随机数值，如果它们匹配，则返回true，然后返回另一组随机变量（因为您正在调用view（），该调用会第二集和第一集）
如果不这样做，则返回“ False”，然后再次调用view，它将再次重新计算随机整数

下面是一个实现所需内容的示例程序（带有注释）：

# Grab the random library
import random

# Create a function to calculate a random number
def create_random_number():
    # No need for a loop, just use x to denote a random number between 1 and 10
    x = random.randint(1,10)
    # Return that random number
    return x

# This is your main function.
# This is sometimes called a "driver" program
def main():
    # Store a random value in the first_val variable
    first_val = create_random_number()
    # Store a random value in the second_val variable
    second_val = create_random_number()

    # If they added up, print out what they were, and that it was a true match
    if first_val == second_val:
        print(first_val, " and ", second_val, " match, this is TRUE")
    # If not, print out what they were, and that it was not a match
    else:
        print(first_val, " and ", second_val, " do not match, this is FALSE")

# Actually execute your main function
main()

希望这有助于回答您的问题。很快，这是因为您正在比较两个值，然后获取不同随机值以进行打印（这有助于依次遍历这些函数的逻辑以及正在发生的事情）。

这是注释您的代码以解释正在发生的事情：

def firstSet():
  import random
  for x in range(1):
    return(random.randint(1,10))

def secondSet():import random
  for x in range(1):
    return(random.randint(1,10))

def view():
  return(secondSet(), firstSet())

def theMatch():
    # This pair here are the first and second random integers
  if secondSet() == firstSet():
    # Now, view() gets called which returns the functions, therefore returning a DIFFERENT set of random integers than the ones being tested
    return(True, view())
  else:
    # Now, view() gets called which returns the functions, therefore returning a DIFFERENT set of random integers than the ones being tested
    return(False, view())

print(theMatch()) 


theMatch()

这是您的代码修复程序，似乎对我有用：

def firstSet():
    import random
    for x in range(1):
        return(random.randint(1,10))

def secondSet():
    import random
    for x in range(1):
        return(random.randint(1,10))

def theMatch():
    firstVal = firstSet()
    secondVal = secondSet()

    if secondVal == firstVal:
    # Now, view() gets called which returns the functions, therefore returning a DIFFERENT set of random integers than the ones being tested
        return(True, secondVal, firstVal)
    else:
    # Now, view() gets called which returns the functions, therefore returning a DIFFERENT set of random integers than the ones being tested
        return(False, secondVal, firstVal)

print(theMatch()) 


theMatch()

随机未返回预期结果

1 个答案: