Question

我目前正在使用python创建语法分析器，该语法分析器将ada程序读取为txt文件，我需要读取数组中的每个元素并将其分配给打印内容。

这是我读取文件并将其放入数组中的代码

with open("resultForOne.txt", "r") as ins:
    array = []
    for line in ins:
        array.append(line)

这就是我打印数组时得到的东西

['lexeme is function _____Token is keyword\n', 'lexeme is a _____Token is identifiers\n', 'lexeme is ( _____Token is symbol\n', 'lexeme is ) _____Token is symbol\n', 'lexeme is x _____Token is identifiers\n', 'lexeme is = _____Token is symbol\n', 'lexeme is 1 _____Token is const\n', 'lexeme is print _____Token is keyword\n', 'lexeme is ( _____Token is symbol\n', 'lexeme is x _____Token is identifiers\n', 'lexeme is ) _____Token is symbol\n', 'lexeme is end _____Token is keyword']

我想阅读每个词素并分配给它打印一些东西

Answer 1

从您的代码中，我认为您正在寻找阅读行

with open("resultForOne.txt", "r") as ins:
    array_ = []
    for line in ins.readlines():
        array_.append(line.strip() )

如果是这样，那么

with open("resultForOne.txt", "r") as ins:
    array_ = [i.strip() for i in ins.readlines()]

您可以在阅读过程中或之后进行打印

for item in array_:
    print(f'[INFO] -> {item}')

如果您想在处理过程中做

with open("resultForOne.txt", "r") as ins:
     array_ = []
     for line in ins.readlines():
         print(f'[INFO] ->  appending {line.strip()}')
         array_.append(line.strip() )

希望这会有所帮助

我如何读取数组中的每个元素并将其分配给某物

1 个答案: