Question

我有一个下表，我需要使用

进行另一个表查询。

期望的查询返回

date Username "Min(sign_time)based on IN" "Max(sign_time)based on out"

原始表

Sign_Date   Employee_UserName   Sign    Sign_Time
27-Mar-19   abdullah.shaaban    In      8:14
27-Mar-19   abdullah.shaaban    Out     15:32

Answer 1

我认为对于相同的日期/用户组合，IN时间戳始终小于OUT时间戳，对吗？总是有一个IN开头，最后一个是out条目？

如果是这样，您可以使用此版本：

select 
   Sign_Date, 
   Employee_UserName, 
   Min(Sign_Time) as IN, 
   Max(Sign_Time) as Out
from Table
group by Sign_Date, Employee_UserName

Answer 2

如果您肯定要使用MS Access，则可以将条件聚合与iif语句一起使用，例如：

select 
    t.sign_date, 
    t.employee_username, 
    min(iif(t.sign = 'In', t.sign_time, null)) as intime,
    max(iif(t.sign = 'Out', t.sign_time, null)) as outtime
from
    YourTable t
group by
    t.sign_date, 
    t.employee_username

另一种解决方案是使用两个相关的子查询：

select
    t.sign_date,
    t.employee_username,
    (
        select min(u.sign_time)
        from YourTable u 
        where
            u.sign_date = t.sign_date and
            u.employee_username = t.employee_username and
            u.sign = 'In'
    ) as intime,
    (
        select max(u.sign_time) 
        from YourTable u 
        where 
            u.sign_date = t.sign_date and
            u.employee_username = t.employee_username and 
            u.sign = 'Out'
    ) as outtime
from
    YourTable t
group by
    t.sign_date, 
    t.employee_username

或者，您可以使用联接：

select 
    a.sign_date, 
    a.employee_username, 
    b.intime, 
    c.outtime
from
    (
        (
            select distinct t.sign_date, t.employee_username
            from YourTable t
        ) a
        left join
        (
            select t.sign_date, t.employee_username, min(t.sign_time) as intime
            from YourTable t
            where t.sign = 'In'
            group by t.sign_date, t.employee_username
        ) b
        on a.sign_date = b.sign_date and a.employee_username = b.employee_username
    )
    left join
    (
        select t.sign_date, t.employee_username, max(t.sign_time) as outtime
        from YourTable t
        where t.sign = 'Out'
        group by t.sign_date, t.employee_username
    ) c
    on a.sign_date = c.sign_date and a.employee_username = c.employee_username

在上述每种情况下，将所有出现的YourTable更改为表的名称。

语法用于MS Access，因为同时标记了SQL Server和MS Access。

基于条件的最大和最小时间的SQL代码（IN / Out）

2 个答案: