如何按天按工资划分获得总工资

Question

这是我的输入表

    Create table #table1(id int, fn varchar(20), startdate varchar(20), id1 varcahr, salary int)
    insert #table1
    select 1, 'Joe', '2019-01-01', 'A', 100
    union select 1, 'Joe', '2019-01-01', 'B',200
    union select 1, 'Joe', '2019-01-05', 'D',400
    union select 1, 'Joe', '2019-01-06', 'E',500
    union select 2, 'john', '2019-01-05', 'F',250
    union select 2, 'john', '2019-01-05', 'F',250
   union select 2, 'john', '2019-01-06', 'G',200
   union select 2, 'john', '2019-01-06', 'H',230
  union select 2, 'john', '2019-01-07', 'I',310

但是我需要类似的输出 按ID，FN，开始日期，薪水分组，并在新列的总计中获得总计

Answer 1

您可以使用sum()的窗口版本。

SELECT id,
       fn,
       startdate,
       id1,
       salary,
       sum(salary) OVER (PARTITION BY id,
                                      fn,
                                      startdate) total
       FROM #table1;